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vodomira [7]
3 years ago
7

The direction of the magnetic field is parallel to the field line at any point in space. A small compass will point in a directi

on perpendicular to the field line.
True
False
Physics
1 answer:
Slav-nsk [51]3 years ago
6 0
I think the answer is false
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What is the difference between condensation and conduction
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Which statements accurately describe trends found in the periodic table
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Batteries are rated in terms of ampere-hours (A·h). For example, a battery that can produce a current of 2.00 A for 3.00 h is ra
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(a) 423 J

The power of the battery is the ratio between the total energy stored (E) and the time elapsed (t):

P=\frac{E}{t}

However, the power is also the product of the voltage (V) and the current (I):

P=VI

Linking the two equations together,

\frac{E}{t}=VI\\E=VIt

Since we know:

V = 9.0 V

I \cdot t = 47.0 A\cdot h

We can calculate the total energy:

E=(9.0 V)(47 A \cdot h)=423 J

(b) 7.79\cdot 10^{-6} dollars

The battery has a total energy of E = 423 J. (2)

1 Watt (W) is equal to 1 Joule (J) per second (s):

1 W = \frac{1 J}{1 s}

so 1 kW corresponds to 1000 J/s:

1 kW = \frac{1000 J}{1 s}

Multiplying both side by 1 hour (1 h):

1 kW \cdot h = \frac{1000 J}{1 s} 1 h

and 1 h = 3600 s, so

1 kWh = \frac{1000 J}{1 s}\cdot 3600 s =3.6\cdot 10^6 J

So we find the conversion between kWh and Joules. So now we can convert the energy from Joules (2) into kWh:

1 kWh = 3.6\cdot 10^6 J = x : 423 J\\x=\frac{1 kWh \cdot 423 J}{3.6\cdot 10^6 J}=1.18\cdot 10^{-4}kWh

And since the cost is $0.0660 per kilowatt-hour, the total cost will be

C=$0.0660\cdot 1.18\cdot 10^{-4} kWh=7.79\cdot 10^{-6} dollars

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4 years ago
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