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Feliz [49]
3 years ago
11

A 160.-kilogram space vehicle is traveling along a straight line at a constant speed of 800. Meters per second. The magnitude of

the net force on the space vehicle is
Physics
2 answers:
Alisiya [41]3 years ago
5 0

<u>Answer:</u> The magnitude of the force on the space vehicle is 0 N

<u>Explanation:</u>

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

F=m\times a

where,

F = force exerted on the space vehicle

m = mass of the space vehicle = 160 kg

a = acceleration of the space vehicle = 0m/s^2    (Speed is constant)

Putting values in above equation, we get:

F=160kg\times 0m/s^2\\\\F=0N

Hence, the magnitude of the force on the space vehicle is 0 N

natulia [17]3 years ago
4 0

Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

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Electromagnetic waves do require a medium to travel.<br><br> True<br> False
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Answer:

The Answer is false

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

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4 years ago
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4 years ago
State how you agree or disagree with the following statement. A good circuit cannot have internal resistance.​
Rashid [163]

Answer: I do

Explanation:

Resistance opposes current thereby reducing the amount of current that flows through a circuit. In other words, it leads to a loss of electrical energy.

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7 0
3 years ago
When a 12 N horizontal force is applied to a box on a horizontal tabletop, the box remains at rest. The force of friction acting
Mrrafil [7]

Answer:

12N

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3 0
3 years ago
A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bum
AleksandrR [38]

Answer:

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Explanation:

#Given the angular velocity, \omega=33\frac{1}{3} rev/min , radius of the record r=0.1m and the distance between any two successive bumps on the groove as d=1.75mm.

The linear speed of the record in meters per second is:

v=\omega r=33\frac{1}{3}\times\frac{2\pi}{60}\times 10\times 10^{_2}\\\\=0.3843m/s\\

#From v above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:

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Hence the bumps hit the stylus at around 199hit/s

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