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antoniya [11.8K]
3 years ago
9

Can you see gas in a bottle

Physics
2 answers:
Galina-37 [17]3 years ago
6 0
Depends on what type of gass
Gelneren [198K]3 years ago
4 0
I think you sometime can but most of the time can't. Most gases are in color containers. That makes it kind of hard to answer this question. I hope this helps!

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Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
4 years ago
What happens to the force between charged and uncharged objects as the distance between them decreases?
MaRussiya [10]

Answer:Thus, if each of the charges were reduced by one-half, the repulsion would be reduced to one-quarter of its former value. Also In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. ... And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.

Hope this helps have a awesome night/day❤️✨

Explanation:

Nothing, until those two objects physically touch each other; contact aligns polarity among the now single shared mass.

(Your question never states if both objects are unique or similar polar charges, so I just assumed they were both neutral objects existing within an electric field.)

So a better question would then be, what is gravity’s relationship with an electric field?

You could solve this with the following: confine the electric field’s volume to a set variable (never increasing nor decreasing in size or shape); density is variable and easily definable. This creates the limit to build upon. This density has to be fluid and has electron mass (full of electrons at rest mass, so with substance but no movement). Within, create a closed system (the hard part in this equation; outside interference like ambient light will eschew results) where each variable of kinetic energy then is accounted for or measurable (including heat and light, and the physical movement of the two objects)

Determine the mass for both objects, calculate gravity for both and each body’s inertia on the other as a sum over distance. record results. Polarity is shared across the masses until there is no longer inertia (one mass or contact).

4 0
3 years ago
Un patinador recorre un parque de 7.2 km de largo a una velocidad de 5 m/s ?cuantas horas duro su recorrido?
pogonyaev
Si velocidad es de 5m/s y esta recorriendo un parke de un tamaño de 7.2 kilometros, su recorrido le duro 1 hora y 44 minutos.

Dividi los kilómetros del parque por la velocidad, dándomela la hora que duró su recorrido

7.2÷5=1.44
4 0
3 years ago
Read 2 more answers
The frequency of the middle c note on a piano is 261.63 hz. What is the wavelength of this note in centimeters? The speed of sou
Sholpan [36]

Answer:

1.31 m

Explanation:

The relationship between frequency and wavelength of a sound wave is

c=f \lambda

where

c is the speed of the wave

f is the frequency

\lambda is the wavelenfth

In this problem, we have

c = 343.06 m/s

f = 261.63 Hz

So we can solve the formula for the wavelength:

\lambda=\frac{c}{f}=\frac{343.06 m/s}{261.63 Hz}=1.31 m

8 0
3 years ago
a large cargo trucks needs to cross a bridge the truck is 30m long, and 3.2 wide, the cargo exerts a force of 54,000 N the bridg
otez555 [7]

Answer:

It isn't safe for the truck to cross the bridge because the pressure exerted by the truck on the bridge is greater than the maximum tolerable pressure for the bridge, 562.5 Pa > 450 Pa.

Explanation:

Pressure is expressed in Force/Area.

So, for the truck, force exerted = 54000 N

Area covered = 30 × 3.2 = 96 m²

Pressure exerted by the truck = 54000/96 = 562.5 Pa

The pressure exerted by the truck on the bridge is greater than the maximum tolerable pressure for the bridge, 562.5 > 450, hence, it isn't safe for the truck to cross the bridge.

5 0
4 years ago
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