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antoniya [11.8K]
3 years ago
9

Can you see gas in a bottle

Physics
2 answers:
Galina-37 [17]3 years ago
6 0
Depends on what type of gass
Gelneren [198K]3 years ago
4 0
I think you sometime can but most of the time can't. Most gases are in color containers. That makes it kind of hard to answer this question. I hope this helps!

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A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be in a s
Greeley [361]

Answer:

a = 4.76 cm

Explanation:

As we know by the law of diffraction through circular aperture

a sin\theta = 1.22 \lambda

here we know that

a = diameter of the aperture

\theta = diffraction angle

\lambda = wavelength

now we have

a = \frac{1.22 \lambda}{sin\theta}

Now in order to find the wavelength we know

\lambda = \frac{c}{f}

\lambda = \frac{343}{9100}

\lambda = 0.0376 m

now we have

a = \frac{1.22(0.0376)}{sin75}

a = \frac{0.046}{0.966}

a = 0.0476 m= 4.76 cm

6 0
3 years ago
If you weighted 130 lbs on Earth how much would you weigh on the moon?
In-s [12.5K]

Answer:

21

Explanation:

Weight on the moon is 16.5 % of weight on earth

Weight on moon = 0.165 * 130

Weight on moon = 21 lbs

3 0
3 years ago
What are the major weather fronts? How do they differ from each other?
dmitriy555 [2]

Answer:

they differ each other bc it is a lot of with earth quakes and everything.

Explanation:

3 0
3 years ago
In which condition the acceleration of a moving vehicle become zero​
Alekssandra [29.7K]

Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

4 0
3 years ago
What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

#SPJ4

6 0
1 year ago
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