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Alborosie
3 years ago
6

Two charges of equal magnitude Q are held a distance d apart. Consider only points on the line passing through both charges.For

parts A through D answer with "Midway between charges", "At the points, where the charges are", aor "There are no such points"A) If the two charges have the same sign, find the location of all points (if there are any) at which the potential (relative to infinity) is zero.B) If the two charges have the same sign, find the location of all points (if there are any) at which the electric field is zero.C) If the two charges have opposite signs, find the location of all points (if there are any) at which the potential (relative to infinity) is zero.D) If the two charges have opposite signs, find the location of all points (if there are any) at which the electric field is zero.
Physics
1 answer:
Burka [1]3 years ago
6 0

Answer:

A

Explanation:

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7 0
2 years ago
Một cần trục có trọng lượng Q = 50 kN cẩu vật nặng có trọng lượng P = 10 kN
lesantik [10]

5

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Explanation:

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8 0
2 years ago
Read 2 more answers
Considerando que você comece a caminhar em velocidade constante, inicialmente a 350 m de um ponto referencial escolhido. Você ca
ExtremeBDS [4]

Answer:

a. S(t)=350−1t

Explanation:

To determine the equation of motion you take into account the general form of motion with constant velocity:

S(t)=S_o+vt    ( 1 )

So is the initial position from a specific reference frame. In this case is 350 m.

v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.

You replace the values of So and v in the equation ( 1 ) and you obtain:

S(t)=350-(1m/s)t

Hence, the answer is:

a. S(t)=350−1t

- - - - - - - - - - - - - - - - - - - - -

Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:

             (1)

Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.

v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.

Você substitui os valores de So ev na equação (1) e obtém:

Portanto, a resposta é:

uma. S (t) = 350-1t, movimento retrógrado

4 0
2 years ago
What is the impulse of a dodgeball hitting a person in the face if it's initial velocity was 10m/s and it's velocity after hitti
Alborosie

Answer:)

Explanation:)

6 0
2 years ago
A 5.0-kg box is pulled by a horizontal force F applied to the top of the box. When the box meets a low doorstep, it begins to ro
NARA [144]

Answer:

the required minimum magnitude of the force F is 21 N

Explanation:

Given the data in the question,

m = 5 kg

width  = 60 cm

height = 80 cm

Let force is F represent in the image below,

so when the block about to rotate normal shifted to edge of cube

mg(w/2) = Fh

F = mg(w/2) / h

we know that g = 9.8 m/s²

we substitute

F = (5 × 9.8 ( 60/2)) / 70

F = (5 × 9.8 × 30 ) / 70

F = 1470 / 70

F = 21 N

Therefore, the required minimum magnitude of the force F is 21 N

5 0
2 years ago
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