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Alborosie
3 years ago
6

Two charges of equal magnitude Q are held a distance d apart. Consider only points on the line passing through both charges.For

parts A through D answer with "Midway between charges", "At the points, where the charges are", aor "There are no such points"A) If the two charges have the same sign, find the location of all points (if there are any) at which the potential (relative to infinity) is zero.B) If the two charges have the same sign, find the location of all points (if there are any) at which the electric field is zero.C) If the two charges have opposite signs, find the location of all points (if there are any) at which the potential (relative to infinity) is zero.D) If the two charges have opposite signs, find the location of all points (if there are any) at which the electric field is zero.
Physics
1 answer:
Burka [1]3 years ago
6 0

Answer:

A

Explanation:

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tia_tia [17]

Answer:

the angle of incident is 40°

Explanation:

NQ is the normal to the mirror, therefore

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PQA = 50°

incident angle = NQA - PQA

90°- 50° = 40°

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Suppose a ray of light traveling in a material with an index of refraction n a reaches an interface with a material having an in
KATRIN_1 [288]

Answer: C and D

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When a ray moves from a dense to a less dense medium, the refracted ray moves away from the normal thus increasing the size of the angle of refraction (total internal refraction occurs when the angle of refraction is 90° and the angle of incidence at this point is known as the critical angle), hence the angle of incidence must be greater than the critical angle.

These points verifies option C and D

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andreev551 [17]
The car is traveling at 60 miles per hour. Theoretically, at this pace, It'll take (B.), 1/2 an hour.


Brainliest?


Hope I helped! ^-^
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3 years ago
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