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rjkz [21]
3 years ago
12

75 kg + 1352 g = ______________g?

Physics
2 answers:
JulsSmile [24]3 years ago
8 0
Answer is 76,352 just look it up
sergeinik [125]3 years ago
7 0

Answer:

76352 g

Explanation:

Start by reducing the first quantity to grams, since a) additions can not be performed among quantities given in different units, and b) the answer is required in grams so better to express everything in grams.

75 kg = 75000 g

Then the addition becomes: 75000 g + 1352 g = 76352 g

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Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

<h3>What is a parallel circuit?</h3>

A parallel circuit is a circuit in which the components are connected to a common junction. This implies that if one bulb goes out in a parallel connection, all the bulbs will go out.

As such, Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

Learn more about parallel connection: brainly.com/question/12400458

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7 0
2 years ago
The total amount of fresh water on earth is estimated to be 3.73 x 10^8 km^3. What is this volume in cubic meters? in cubic feet
Burka [1]
One km^3 is 1,000,000,000 m^3=10^9 m^3 hence 3.73 10^8 km^3 is 3.73 10^17 m^3

One meter is 3.28084 feet hence 1 m^3 is (3.28084)^3 feet

Thus 3.73 10^8 km^3 is 3.73*35.315 10^17 = 132 cubic feet
5 0
3 years ago
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A theory is a hyothesis that has been varified by multiple investigations. <br> True or false
irakobra [83]
<span>A theory is a hyothesis that has been varified by multiple investigations. 

true</span>
7 0
3 years ago
If the magnitude of the electric field in air exceeds roughly 3 ✕ 106 n/c, the air breaks down and a spark forms. for a two-di
Vlad1618 [11]

Answer: 39.8 μC

Explanation:

The magnitude of the electric field generated by a capacitor is given by:

E = \frac{V}{d}

d is the distance between the plates.

For a capacitor, charge Q = CV where C is the capacitance and V is the voltage.

C =\frac{\epsilon_o A }{d}

where A is the area of the plate and ε₀ is the absolute permittivity.

substituting, we get

E = \frac{Q}{\epsilon_o A}

It is given that the magnitude of the electric field that can exist in the capacitor before air breaks down is, E = 3 × 10⁶ N/C.

radius of the plates of the capacitor, r = 69 cm = 0.69 m

Area of the plates, A = πr² = 1.5 m²

Thus, the maximum charge that can be placed on disks without a spark is:

Q = E×ε₀×A

⇒ Q = 3 × 10⁶ N/C × 8.85 × 10⁻¹² F/m × 1.5 m² = 39.8 × 10⁻⁶ C = 39.8 μC.

8 0
3 years ago
An archer pulls a bowstring back a distance of 20 cm with an average force of 75 N. The arrow has a mass of 20.0 g. When he rele
Masja [62]

To solve this problem we will apply the concepts related to the work theorem for which it is defined as the product of Force and distance. In turn, we will use the energy conservation theorem for which the applied work must be equivalent to the total kinetic energy on the body.

The work is defined as

W = Fd

Here,

F = Force

d = Displacement

Replacing with our values we have that

W = 75*0.2

W = 15J

Now by conservation of energy,

W = KE

W = \frac{1}{2}mv^2

15 = \frac{1}{2} (20*10^{-3}kg)(v^2)

Solving for v,

v = 10\sqrt{15}

v = 38.72 \approx 39

Therefore the correct answer is D.

8 0
4 years ago
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