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3 years ago

10

In Kevin study he knows that each participant has an equal probability of being placed into each of his conditions Kevin must ha

ve used

1 answer:

kodGreya [7K]3 years ago

5 0

Answer:

Kevin must have used simple random sampling.

Explanation:

We can say that Kevin used simple random sampling. This is because this type of sampling allows elements to be taken from a population in a completely random way, to form a sample. In this case, each element, or individual, as shown in the question above, has the same probability of being selected to compose the sample, since this selection is completely random.

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In a Young’s interference experiment, the two slits are separated by 0.150 mm and the incident light includes two wavelengths: l

dezoksy [38]

Answer:

2.52 × 10⁻² cm

Explanation:

The distance of bright fringe from the center of the screen is given by the formula

$y = \frac{m\lambda D}{d}$

Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the

slits is d.

Separation between the slits, d = 0.15 mm

$= 0.15 * 10^{-3} m$

Distance of the screen from the slits = 1.40 m

We have a wavelength, λ1 = 540 nm

= $540 * 10^{-9} m$

By substituting all these values in the above equation we get

y1 = mλD/d

$y1 = m(540 \times 10^{-9} m)(1.40 m)/(0.15 \times 10^{-3} m)$

$y1 = m(5.04 * 10^{-3} m)$

We have a wavelength, λ2 = 450 nm

= $450 * 10^-9 m$

By substituting all these values in the above equation we get

$y_2 = \frac{m\lambda D}{d}$

$y_2 = m(450 * 10^{-9} m)(1.40 m)/(0.15 * 10^{-3} m)$

$y_2 = m'(4.20 * 10^{-3} m)$

According to the problem, these two distance are coincides with each other.

So,

$y_1 = y_2$

$m(5.04 * 10^{-3} m) = m'(4.20 * 10^{-3} m)$

by testing values, the above equation is satisfied only when, m = 5 and m' = 6

Then from the above we have

y1 = y2 = 0.0252 m

= 2.52 × 10⁻² cm

8 0

3 years ago

During aerobic activity, if your heart rate is lower than the lower limit, you are ___________________.

soldier1979 [14.2K]

Not pushing yourself hard enough is the answer since your heart rate doesn't even hit your lower minimum.
Pushing yourself to the limit is at your max heart rate.
Just at the right spot is at your max heart rate.
Pushing yourself too hard is above your max heart rate.

4 0

4 years ago

A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonba

Naddik [55]

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

5 0

3 years ago

A dock worker applies a constant horizontal force of 81.0 N to a block of ice on a smooth horizontal floor. The frictional force

AnnZ [28]

Answer:

The correct answer is:

(a) 84.240 kg

(b) 24.038 m

Explanation:

The given values are:

Force,

F = 81.0 N

Distance,

S = 13.0 m

Time,

t = 5.20 s

As we know,

The acceleration of mass will be:

⇒ $a=\frac{2S}{t^2}$

On substituting the given values, we get

⇒ $=\frac{2\times 13.0}{(5.20)^2}$

⇒ $=\frac{26}{27.04}$

⇒ $=0.961538 \ m/s^2$

(a)

The mass of the block will be:

⇒ $m=\frac{F}{a}$

On substituting the given values, we get

⇒ $=\frac{81.0}{0.961538}$

⇒ $=84.240 \ kg$

(b)

The final velocity after a given time i.e.,

t = 5.00 s

⇒ $v=at$

On substituting the values, we get

⇒ $=0.961538\times 5.00$

⇒ $=4.8076 \ m/s$

In time, t = 5.00 s

The distance moved by the block will be:

⇒ $d=vt$

On putting the values, we get

⇒ $=4.8076\times 5.00$

⇒ $=24.038 \ m$

5 0

3 years ago

What two factors affect the gravitational force between two objects

Marina86 [1]

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.Explanation:

7 0

3 years ago

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