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3 years ago

9

Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be?

1 answer:

jok3333 [9.3K]3 years ago

3 0

Answer: 3.26 light years

Explanation:

Each star has a parallax of one arcsecond at a distance of one parsec, which is equivalent to 3.26 light years.

so the parallax of 1 arcsecond will be at a distance of <em>1/1 × 3.26 light years</em>

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Why do the constellations seem to move around in the sky?.

Gnoma [55]

Answer: As Earth spins on its axis, we, as Earth-bound observers, spin past this background of distant stars. As Earth spins, the stars appear to move across our night sky from east to west, for the same reason that our Sun appears to “rise” in the east and “set” in the west.

Explanation:

8 0

3 years ago

In what state must matter exist for fusion reactions to take place

steposvetlana [31]

Answer:

Plasma

Explanation:

For a fusion reaction to take place, there must be conditions in which the particles have extreme thermal kinetic energies, in this way the collisions that cause the nuclear fusion are generated. Therefore, it is necessary to reach very high temperatures, in which the state of matter will necessarily be plasma.

8 0

3 years ago

54 km/h is equal to

pogonyaev

$\Huge{\underline{\underline{\mathfrak{\green{AnsWeR:}}}}}$

1 km/h = 5/18 m/s

54 km/h = 54×5/18 m/s

<h2>= 15 m/s</h2>

7 0

3 years ago

A car is driving towards an intersection when the light turns red. The brakes apply a constant force of 1,398 newtons to bring t

dmitriy555 [2]

Answer:

the initial velocity of the car is 12.04 m/s

Explanation:

Given;

force applied by the break, f = 1,398 N

distance moved by the car before stopping, d = 25 m

weight of the car, W = 4,729 N

The mass of the car is calculated as;

W = mg

m = W/g

m = (4,729) / (9.81)

m = 482.06 kg

The deceleration of the car when the force was applied;

-F = ma

a = -F/m

a = -1,398 / 482.06

a = -2.9 m/s²

The initial velocity of the car is calculated as;

v² = u² + 2ad

where;

v is the final velocity of the car at the point it stops = 0

u is the initial velocity of the car before the break was applied

0 = u² + 2(-a)d

0 = u² - 2ad

u² = 2ad

u = √2ad

u = √(2 x 2.9 x 25)

u =√(145)

u = 12.04 m/s

Therefore, the initial velocity of the car is 12.04 m/s

7 0

3 years ago

How much heat is needed to increase the internal energy of a gas in a piston by 4,736J if the gas does 750J of work on the envir

kykrilka [37]

The heat absorbed by the gas is 5486 J

Explanation:

We can solve this problem by using the 1st law of thermodynamics, which states that the change in internal energy of a gas is given by:

$\Delta U = Q-W$

where:

$\Delta U$ is the change in internal energy

Q is the heat absorbed by the gas

W is the work done by the gas

In this problem, we have:

$\Delta U = +4736 J$ is the increase in internal energy of the gas

$W=+750 J$ is the work done by the gas (positive because the gas is doing work on the surroundings, by expanding)

Solving for Q, we find the heat needed:

$Q=\Delta U + W = 4736+750=5486 J$

And the positive sign tells us that this heat is absorbed by the gas.

Learn more about thermodynamics:

brainly.com/question/4759369

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#LearnwithBrainly

6 0

4 years ago