Answer: A Radium
Explanation:
Thorium-232 is an alpha-emitting radionuclide, which decays to radium-228, which is a beta emitter with a half-life of about six years.
Answer:
by measuring calender we can find
Explanation:
Answer:
Zero
Explanation:
Average velocity is given by:

where
d is the displacement of the trip
t is the time it takes for the trip to complete
In this problem, the net displacement of the swimmer is zero. In fact:
- First, he swims 30.0 m in the north direction
- Then, he travels back (-30.0 m) in the south direction, to the starting position
Since the final position is equal to the starting position, the displacement is zero:
d = 0
And therefore, the average velocity is also zero.
Answer:
hmm let's see
Explanation:
ok, ill use the second equation of motion, u see its quite simple
recall that
average velocity= u+v/2
now think of that v like a box you can can call it velocity lol obviously its velocity
now remember the first equation of motion which is
v=u+at now this is inside the box, now you have to replace the v with it
then it becomes u+u+at/2
now u notice there are two initial velocity u know what to do with that
now it becomes
2u + at/2 now since the numerator applies to both then you can simplify it like this
2u/2+at/2
all the same the pont im trying to make is that you can use imaginative ways to mater derivation you can also reverse it if you don't unferstand you can drop your number
Both momentum and kinetic energy are conserved in elastic collisions (assuming that this collision is perfectly elastic, meaning no net loss in kinetic energy)
To find the final velocity of the second ball you have to use the conversation of momentum:
*i is initial and f is final*
Δpi = Δpf
So the mass and velocity of each of the balls before and after the collision must be equal so
Let one ball be ball 1 and the other be ball 2
m₁ = 0.17kg
v₁i = 0.75 m/s
m₂ = 0.17kg
v₂i = 0.65 m/s
v₂f = 0.5
m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f
Since the mass of the balls are the same we can factor it out and get rid of the numbers below it so....
m(v₁i + v₂i) = m(v₁f + v₂f)
The masses now cancel because we factored them out on both sides so if we divide mass over to another side the value will cancel out so....
v₁i + v₂i = v₁f + v₂f
Now we want the final velocity of the second ball so we need v₂f
so...
(v₁i + v₂i) - v₁f = v₂f
Plug in the numbers now:
(0.75 + 0.65) - 0.5 = v₂f
v₂f = 0.9 m/s