Answer:
Core
Radiative zone
Convective zone
Photosphere
Chromosphere
Transient region
Corona
Ranks of layers based on their distance from the sun’s center
1st-corona
2nd-Transient region
3rd-chromosphere
4th-Photosphere
5th-convective zone
6th-radiative zone
7th-core
Answer:
<em>The total time is: t=451.22 sec</em>
<em>The average speed is: V=34.57 m/s</em>
Explanation:
<u>Average speed</u>
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

The total time is:


The average speed is:


Answer:
The force exerted by the child is 38.25 Newton
Explanation:
We use the formula F=mxa (m=mass and a= aceleration):
F= 45kg x 0,85 m/s2=38, 25 kgxm/s2= <em>38, 25 N</em>
Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)

B)
![P=100*5\\P=500[kg*m/s]](https://tex.z-dn.net/?f=P%3D100%2A5%5C%5CP%3D500%5Bkg%2Am%2Fs%5D)
C)
![P=1200*15\\P=18000[kg*m/s]](https://tex.z-dn.net/?f=P%3D1200%2A15%5C%5CP%3D18000%5Bkg%2Am%2Fs%5D)
D)
![P=15*1000\\P=15000[kg*m/s]](https://tex.z-dn.net/?f=P%3D15%2A1000%5C%5CP%3D15000%5Bkg%2Am%2Fs%5D)
From higher to lower momentum
C,D,B,A
Picture #1:
GPE = (mass) x (gravity) x (height)
GPE = (2 kg) x (9.8 m/s²) x (40 m) = 784 joules
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (5 m/s)²
KE = (1 kg) (25 m²/s²) = 25 joules
Picture #2:
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (10 m/s)²
KE = (1 kg) (100 m²/s²) = 100 joules
Picture #3:
GPE = (mass) x (gravity) x (height)
GPE = (20 kg) x (9.8 m/s²) x (2 m) = 392 joules
KE = (1/2) (mass) (speed²)
KE = (1/2) (20 kg) (5 m/s)²
KE = (10 kg) (25 m²/s²) = 250 joules
Picture #4:
GPE = (mass) x (gravity) x (height)
98 joules = (1 kg) x (9.8 m/s²) x (height)
Height = (98 joules) / (1 kg x 9.8 m/s²)
Height = 10 meters
Picture #5:
GPE = (mass) x (gravity) x (height)
39,200 Joules = (mass) x (9.8 m/s²) x (20 m)
Mass = (39,200 joules) / (9.8 m/s² x 20 m)
Mass = 200 kg