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3 years ago

8

The rectangular region of the xy plane shown has nonuniform surface charge density σ = σ0 (1+ y b), where σ0 is a constant. Find

the net charge.

1 answer:

sergiy2304 [10]3 years ago

8 0

Answer:

This is net charge on the surface is Q = σ₀ x (y + 2by²)

Explanation:

The surface charge density is defined as the amount of charge Q per unit area A

σ = dq / dA

dq = σ dA

Since the surface is a rectangular region we use an xy coordinate system so the area difference

dA = dxdy

dq = σ dx dy

We replace, evaluate the integral

∫ dq = ∫ σ₀ (1 + yb) dxdy

realizamos laintegral de dx

Q -0 =σ₀ ∫ (1 + yb) (x-0) dy

Where we evaluate We must recognize that the charge Q must be zero by the time X = 0 and Y = 0. At the starting point Q = 0 for x = 0

We perform the other integral (dy)

Q = σ₀ x (y + 2y² b)

Evaluated between Y = 0 and Y = y

Q = σ₀ x (y + 2by²)

This is net charge on the surface

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2 years ago

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2 years ago

An automobile with a standard differential turns sharply to the left. The left driving wheel turns on a 20-m radius. Distance be

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Now, we assume that

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Formula for angular velocity of inner wheel w = ,

Formula for angular velocity of outer wheel w =

Now, for inner wheels

w =

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u = $V \times \frac{(R - d)}{R}$

= $V \times (1 - \frac{d}{R})$

If radius of wheel is r it will cover distance in one min.

Since, velocity of wheel is u it will cover distance u in unit time(min)

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3 years ago

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Talja [164]

Answer:

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$\omega_f = 2\pi f$

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3 years ago