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2 years ago

Using the picture above, which ball has the greatest potential energy?

Physics

1 answer:

weqwewe [10]2 years ago

4 0

Ball 4 because the higher the elevation is the greater the potential energy it has

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Two trolleys are moving in the same direction along a track. Trolley 1 has a momentum of 2 kg m/s and Trolley 2 has a momentum o

motikmotik

Hi there!

Recall the conservation of momentum:

$\large\boxed{m_1v_1 + m_2v_2 = m_1v_1' + m_2v_2'}}$

For this type of inelastic collision:

$\large\boxed{m_1v_1 + m_2v_2 = v_f(m_1 + m_2)}}$

Thus, the initial momentum equal the final momentum if there are no external forces.

We can begin by writing out this problem:

$2 + 6 = v_f(m_1 + m_2)$

$8 = 2(m_1 + m_2)\\\\m_1 + m_2 = \boxed{4 kg}$

8 0

2 years ago

Tool used to measure time

charle [14.2K]

Answer:

clock

Explanation:

personal experience

6 0

2 years ago

Read 2 more answers

Sketch a position-time graph for a bear starting

Dmitrij [34]

Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

3 0

3 years ago

A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering

Black_prince [1.1K]

<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y$ is the height of the stone at 6s (the value we want to find)

$y_{o}=925ft$ is the initial height of the stone

$V_{o}=20ft/s$ is the initial velocity of the stone

$t=6s$ is the time at which we need to find the height

$g=32ft/s^{2}$ is the acceleration due to gravity

Having this clear, let's find $y$ from (1):

$y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2}$ (2)

Finally:

$y=469ft$ This is the height of the stone at t=6s

4 0

2 years ago

At what altitude above the earth's surface would the acceleration due to gravity be 4.9 m/s^2? Assume the mean radius of the ear

Mandarinka [93]

We apply the gravity calculation expressed in the formula: g=GM/r2
where G is the gravitational constant, m is the mass and r is the radius
r=√GM/g
(1) Radius = √6.674e-11*5.972e24/8 = 7058 kms Earth radius or surface of earth from center of earth= 6400 kmsSo r= 658 kms from surface of earth.
Gravity 8m/s2 will be at 658 kms from surface of earth.
(2) half gravity= 9.8/2= 4.9 m/s2 Radius=√6.674e-11*5.972e24/4.9 = 9019 kms Half Gravity will exist at 9019-6400= 2619 kms from surface of earth.

4 0

3 years ago