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Vikki [24]
3 years ago
6

For each of the following reactions, identify another quantity that is equal to DeltH degree rxn.

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer:

1) CH_{4}(g) + 2O_{2}(g) --->CO_{2}(g) + 2H_{2}O(l)

Enthalpy of combustion.

2) CH_{4}(g)----> C(g) + 4H(g)

4x bond energy of C - H

3) C(graphite) + 2H_{2}(g)--->CH_{4}(g)

enthalpy of formation of CH₄(g)

4) C(g) + 4H(g) ---> CH_{4}(g)

- 4x bond energy of C - H

Explanation:

The enthalpy of reaction is the heat change during the reaction.

It can be:

a) Enthalpy of combustion : the heat change during complete burning of one mole of a substance in presence of oxygen.

CH_{4}(g) + 2O_{2}(g) --->CO_{2}(g) + 2H_{2}O(l)

b) Enthalpy of formation: the heat change during formation of one mole of a substance from its constituent elements in their native state.

C(graphite) + 2H_{2}(g)--->CH_{4}(g)

c) The difference in the bond energies of reactants and products.

enthalpy= sumofbondenergiesofreactants-sumofbondenegiesofproducts

For:

C(graphite) + 2H_{2}(g)--->CH_{4}(g)

Enthalpy=[0]-[4XbondenergyofC-H]=-4XbondenergyofC-H

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1. Find the molar mass of the compounds<br>a. K2Cro4​
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Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,
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Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

3 0
2 years ago
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