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vivado [14]
3 years ago
7

The Balmer Series of lines in the hydrogen atom was very important in the history of physics and astronomy. What made it so impo

rtant?
A) It helped Rutherford explain the workings of the atomic nucleus.
B) Balmer's experiments with these lines helped prove Wien's Law.
C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum.
D) The Balmer series of lines can only be observed from outer space; so the competition to see these lines led to the space race.
E) Mr. Balmer never got the Nobel prize, which made everyone in the field of spectroscopy so angry, they worked extra hard.
Chemistry
1 answer:
True [87]3 years ago
3 0

Answer:

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum

Explanation:

The Balmer Series of lines in the hydrogen atom was very important in the history of physics and astronomy. What made it so important?

A) It helped Rutherford explain the workings of the atomic nucleus.

B) Balmer's experiments with these lines helped prove Wien's Law.

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum.

D) The Balmer series of lines can only be observed from outer space; so the competition to see these lines led to the space race.

E) Mr. Balmer never got the Nobel prize, which made everyone in the field of spectroscopy so angry, they worked extra hard.

the most appropriate will be

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum

Balmer series of hydrogen lines. These lines are emitted when the electron in the hydrogen atom moves from the orbital n = 3 or greater shell down to the n = 2 shell/orbit. ... Energy is emitted from the atom when the electron leaps from one orbit to another closer to the nucleus.

Wiens law has to do with the radiation  of a black body.

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Answer:

to do day-to day activities easily and make surrounding comfortable for man

Explanation:

as an example , binary numbers help to work computers ,calculators.they help us lot .

scientific methods also need to write large and small numbers in short ways .so, scientists find various patterns .

6 0
2 years ago
Why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions
Alika [10]
<span>Scientists ignore the forces of attraction between particles in a gas under ordinary conditions</span><span> because the particles in a gas are apart and moving fast, rather than clustered and moving slow, therefore the forces of attraction are too weak to have a visible effect.</span>
3 0
3 years ago
Calcium is a group 2 element. Chlorine is a group 7 element. They form an ionic compound called
kondaur [170]

Answer:

CaCl2

Explanation:

For every calcium there's 2 chlorine

7 0
3 years ago
What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according
ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

<u>Step 1: </u>The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

<u>Step 2: </u>Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

<u>Step 3: </u>Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

<u>Step 4: </u>Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M  = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0
3 years ago
What is the equilibrium constant expression for the ksp of sr3(po4)2?
Eddi Din [679]

The equilibrium constant expression for KSP of Sr3(PO4)2 is


KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}


Explanation


write the ionic equation for Sr3(PO4)2


Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-


KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

7 0
3 years ago
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