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swat32
3 years ago
14

PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

Engineering
2 answers:
Oksi-84 [34.3K]3 years ago
8 0
The first one is the answer
Step2247 [10]3 years ago
8 0
First one :/ dumb so don’t ye
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What happen to the clutch system when you step-on and releasing the clutch pedal?​
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Answer:

Step On: Your foot forces the clutch pedal down and then causes it to take up the slack. This, in turn, causes the clutch friction disk to slip, creating heat and ultimately wearing your clutch out.

Step Off: When the clutch pedal is released, the springs of the pressure plate push the slave cylinder's pushrod back, which forces the hydraulic fluid back into the master cylinder.

7 0
3 years ago
A resistivity meter is measured in
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Ohms ..................
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3 years ago
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Assume that television broadcasts are nonrival and nonexcludable (some TV stations, such as those on cable TV, are excludable, b
ryzh [129]

Answer: Advertising acts in a method similar to a fee. People who watch TV broadcasts must watch ADs. TV stations turn this into money by selling airtime to advertisers.

Explanation:

A non-rival good is a good whose consumption by one person does not reduce the remaining quantity available. An example is a street light.

For non-excludable goods, it is impossible to prevent everyone from enjoying the benefits of the good. An example is a lighthouse. This is where the free rider problem comes in.

A free rider is someone enjoying the benefits of a good without paying for it.  When a good is both non-rival and non-excludable, it is convenient for consumers to enjoy the benefit without paying for it.

If TV broadcasts are both non-rival and non-excludable, everybody can choose to become a free rider. Advertising can solve this problem by converting free riders to potential buyers of goods or services advertised during broadcasts. This way, stations can generate revenue by selling airtime.

3 0
4 years ago
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Applying the Entropy Balance: Closed Systems Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston–
Mrrafil [7]

Answer:

a) the amount of energy produced in kJ/K is 0.73145 kJ/K

b) the amount of energy produced in kJ/K is 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

Explanation:

Draw the T-s diagram.

a)

C_p = 0.939 kJ/kg.K , m = 5 kg , T₂ = 520 K , T₁ = 280

R = [8.314 kJ / 44.01 kg.K] , P₂ = 20 bar , P₁ = 2 bar

Δs = m[c_p ln(\frac{T_2}{T_1}) - Rln(\frac{P_2}{P_1})]

Substitute all parameters in the equation

Δs = 5[(0.939) ln(\frac{520}{280}) - (\frac{8.314}{44.01})ln(\frac{20}{2})]

Δs = 5 kg × 0.14629 kJ/kg.K

    = 0.73145 kJ/K

b)

Δs = m[\frac{s^0(T_2) - s^0(T_1)}{M} - Rln(\frac{P_2}{P_1})]

Where T₁ = 280 K , s°(T₁) = 211.376 kJ/kmol.K

           T₂ = 520 K , s°(T₂) = 236.575 kJ/kmol.K

R = [8.314 kJ / 44.01 kg.K] , M = 44.01 kg.K , P₂ = 20 bar , P₁ = 2 bar

Δs = 5[\frac{236.575 - 211.376}{44.01} - (\frac{8.314}{44.01})ln(\frac{20}{2})]

    = 5 kg (0.13795 kJ/kg.K)

    = 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

7 0
4 years ago
I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?
GuDViN [60]

Answer:

  your answer is correct

Explanation:

You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...

 A B Y

 0 0 1

 0 1 0

 1 0 0

 1 1 1

That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.

8 0
3 years ago
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