Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v = 
x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
X = total horizontal distance = 25 ft
Y = total vertical distance = 125 ft
x = horizontal distance = 1 ft
y = vertical distance = ?
using the equation
y = (Y/X) (x)
inserting the values
y = (125/25) (1)
y = 5 ft
hence for each horizontal foot, the average height change is 5 ft
or
25 ft horizontal distance traveled = 125 ft vertical distance dropped
dividing both side by 25
25 ft horizontal distance traveled/25 = 125 ft vertical distance dropped/25
1 foot horizontal distance traveled = 25 ft vertical distance dropped
Answer:
5
Explanation:
a= v ÷ t which when you insert it into the equation it should be a= 40m/s ÷ 8s
Answer:
yes
Explanation:
it can end up stressing you out, causing a fight or argument
