Solve Fast Please!!!!!!!!!!!!!! ok thanks, Bye (2x−5)^2−.5x<(2x−1)(2x+1)−15

Mathematics

1 answer:

Andrews [41]3 years ago

8 0

Keep these rules in mind:

(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
(a + b)(a - b) = a² - b²

Firstly, solve the exponent and multiplication:

$4x^2-20x+25-0.5x$

Next, combine like terms:

$4x^2-20.5x+25$

Next, subtract 4x² on both sides:

$-20.5x+25$

Next, subtract 25 on both sides:

$-20.5x$

Lastly, divide both sides by -20.5. And since you are dividing by a negative, flip the inequality sign:

$x>2$

Your answer is x > 2.

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