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Leona [35]
3 years ago
10

A baseball player applies a force of 200N onto a baseball. Determine the time that baseball player exerts on the baseball if an

impulse of 50 Ns is exerted on the baseball.
Physics
2 answers:
Anestetic [448]3 years ago
8 0

Answer:

Time, t = 0.25 seconds  

Explanation:

Given that,

Force applied by a baseball player, F = 200 N

We need to find the time that baseball player exerts on the baseball if an impulse of 50 Ns is exerted on the baseball. The impulse exerted on the baseball is given by :

J=F\times t

t is time taken

t=\dfrac{J}{F}\\\\t=\dfrac{50\ N-s}{200\ N}\\\\t=0.25\ s

So, the time for which the baseball player exerts on the baseball is 0.25 seconds.

jolli1 [7]3 years ago
3 0

Answer:A football player kicks a ball with a force of 50N. Find the impulse on the ball if his foot stays in contact with the football for ... A hockey player applies an average force of 80N to a 0.25kg hockey puck for a ... She uses a hammer to drive the nail into the wall. ... A 0.5kg baseball experiences a 10N force for a duration of 0.1s.

Explanation:

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3 years ago
How do noise canceling headphones work?
postnew [5]

Answer:

B.) by interfering with sound waves

Explanation:

As we know that the interference of sound waves is of two types

1). constructive interference

2). destructive interference

now we know that constructive interference means the resultant intensity will be more than the intensity of interfering waves as here two waves are in same phase.

In destructive interference the resultant of two waves is given by the minimum resultant of the intensity as here the phase of two waves are opposite to each other.

So we will say that

I = \sqrt{(I_1 + I_2 + 2\sqrt{I_1I_2}cos\theta)}

here in case of noise cancelling headphones we know that the phase of noise is always made in opposite phase with the sound which is used to cancelled the noise.

This will reduce the noise and we will get a clear sound

5 0
3 years ago
Read 2 more answers
The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on
sammy [17]

Answer: First, we determine the circumference of the Mars by the equation below.  

                                     C = 2πr

Substituting the known values,

                                     C = 2(π)(3,397 km) = 6794π km

To determine the tangential speed, we divide the circumference calculated above by the time it takes for Mars to complete one rotation and that is,

                   tangential speed = 6794π km / 24.6 hours = 867.64 km/h

6 0
3 years ago
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Which describes an interaction within the musculoskeletal system?
rosijanka [135]

Answer:

The musculoskeletal system involves the complex interactions of muscles, bones, and connective tissues.

When a muscle contracts, a bone will move. When a bone contracts, a muscle will move. When a ligament contracts, a tendon will move.

7 0
3 years ago
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If 2.40 g of KNO3 reacts with sufficient sulfur (S8) and carbon (C), how much P-V work will the gases do against an external pre
creativ13 [48]

Answer:

-112.876J

Explanation:

In order to solve this question, we would need to incorporate Stoichiometry, which involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Here's a balanced equation for the reaction:

16KNO_3(s) + 24C(s) + S_8(s)    \to 24CO_2(g) + 8N_2(g) + 8K_2S(s)

Let us define P - V work as;

w_{pv} = - P_{external}  \triangle Volume

where  \triangle (Volume) = (V_{final} - V_{initial})

External pressure is given as  1.00atm , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,  V_i = 0.

To find the volume of the products, we need to first find the amount of moles of the product made from  2.40_gKNO_3, using the molar mass of  KNO_3  which is 101.1032 g/mol  

2.40_gKNO_3 . {\frac{1molKNO_3}{101.1032_g}} = 0.0237molKNO_3

Now let us convert moles of  KNO_3  into moles of CO_2 and N_2  using the stoichiometric ratios from our balanced equation of the reaction.

0.0237molKNO_3 . {\frac{24molCO_2}{16molKNO_3}} = 0.0356molCO_2

0.0237molKNO_3 . {\frac{8molN_2}{16molKNO_3}} = 0.01185molN_2

K_2S is not factored into the volume calculation because it is a solid.

Now let us also convert the moles of  CO_2  and  N_2 into grams using their respective molar masses.

0.0356molCO_2 . {\frac{44.01_g}{1molCO_2}} = 1.567_gCO_2

0.01185molN_2 . {\frac{28.014_g}{1molN_2}} = 0.332_gN_2

We will now proceed to convert grams into volume using the density values provided.

1.567_gCO_2 . {\frac{1L}{1.830_g}} = 0.856LCO_2

0.332_gN_2 . {\frac{1L}{1.165_g}} = 0.285LN_2

Summing up the two volumes, we get the final volume

0.856L + 0.258L = 1.114L = V_f

Plugging everything into the w_{pv} equation, we get:

w_{pv} = -1atm(1.114L - 0L) = -1.114L.atm

Finally, let us convert L.atm into joules using the conversion rate of;

1L.atm = 101.325J\\-1.114L.atm. {\frac{101.325J}{1L.atm}} = -112.876J

7 0
4 years ago
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