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Leona [35]
3 years ago
10

A baseball player applies a force of 200N onto a baseball. Determine the time that baseball player exerts on the baseball if an

impulse of 50 Ns is exerted on the baseball.
Physics
2 answers:
Anestetic [448]3 years ago
8 0

Answer:

Time, t = 0.25 seconds  

Explanation:

Given that,

Force applied by a baseball player, F = 200 N

We need to find the time that baseball player exerts on the baseball if an impulse of 50 Ns is exerted on the baseball. The impulse exerted on the baseball is given by :

J=F\times t

t is time taken

t=\dfrac{J}{F}\\\\t=\dfrac{50\ N-s}{200\ N}\\\\t=0.25\ s

So, the time for which the baseball player exerts on the baseball is 0.25 seconds.

jolli1 [7]3 years ago
3 0

Answer:A football player kicks a ball with a force of 50N. Find the impulse on the ball if his foot stays in contact with the football for ... A hockey player applies an average force of 80N to a 0.25kg hockey puck for a ... She uses a hammer to drive the nail into the wall. ... A 0.5kg baseball experiences a 10N force for a duration of 0.1s.

Explanation:

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Answer:

The speed of light changes as it moves between media. This causes refraction. Angles of refraction can be calculated using known speeds or wavelengths. Beyond the critical angle, light is reflected.

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2 years ago
A recipe for a sweet tea calls for 3 cups of sugar when you place a sugar into the tea it doesn't dissolve. How could you use di
barxatty [35]

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Blizzard [7]

Answer: D

Neither A nor B

Explanation:

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2 years ago
An open train car moves with speed 18.5 m/s on a flat frictionless railroad track, with no engine pulling the car. It begins to
olga2289 [7]

Answer:

The speed decreases.

Explanation:

This can be explained using the conservation of linear momentum.

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the initial linear momentum is

m_{1}v_{1}

where m_{1} is the initial mass of the train, and v_{1} the initial speed of the train.

And linear momentum after the water filled the train car is

m_{2}v_{2}

where m_{2} is mass of the train after the  rain, and v_{2} the speed of the train after the rain

<u>the equality must be fulfilled:</u>

m_{1}v_{1}=m_{2}v_{2}

We know that if water is added to the train, m_{2} that is the mass after the water is added, is greater than m_{1} which is the mass of the train without the water.

Therefore, in order for the conservation of the linear momentum to be fulfilled: m_{1}v_{1}=m_{2}v_{2}

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3 0
3 years ago
Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?
noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

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3 0
3 years ago
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