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3 years ago

Dissolving potassium chlorate (KClO3) is even more endothermic than potassium chloride.

Chemistry

1 answer:

zhenek [66]3 years ago

5 0

Answer:

The mass of KClO₃ that will absorb the same heat as 5 g of KCl is 3.424 g

Explanation:

Here we have

Heat of solution of KClO₃ = + 41.38 kJ/mol.

Heat of solution of KCl (+17.24 kJ/mol)

Therefore, 1 mole of KCl absorbs +17.24 kJ during dissolution

Molar mass of KCl = 74.5513 g/mol

Molar mass of KClO₃ = 122.55 g/mol

74.5513 g of KCl absorbs +17.24 kJ during dissolution, therefore, 5 g will absorb

$\frac{17.24}{74.5513 } \times 5 \, \, kJ \, or \, 1.156 \, kJ$

Therefore the amount of KClO₃ to be dissolved to absorb 1.156 kJ of energy is given by

122.55 g of KClO₃ absorbs + 41.38 kJ, therefore,

$\frac{1.156}{41.38} \times 122.55 \, g = 3.424 \, g$

Therefore the mass of KClO₃ that will absorb the same heat as 5 g of KCl = 3.424 g.

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alex41 [277]

Original molarity was 1.7 moles of NaCl

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Given Information:

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Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity

1. Solve for the molarity of the original (concentrated) solution.

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Convert the given information to the appropriate units before plugging in and solving for molarity.

Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)

2. Solve for the molarity of the final (diluted) solution.

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Vladimir79 [104]

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