Molar mass FeTiO3 => 151.7102 g/mol
atomic mass Ti => 47.867 u
% ( atomic mass Ti / molar mass FeTiO3 ) x 100
= ( 47.867 / 151.7102) x 100
= 0.3155 x 100
= 31.55 % of Ti
hope this helps!
Double the friction of the object
Fire Hazard would be the correct answer
Explanation:
The given data is as follows.
Density of vinegar = 1.0 g/ml
Specific heat capacity = 4.25 
= 
, and 
= 
Relation between enthalpy and specific heat is as follows.
Hence, putting the values into the above formula as follows.
= 
(as density = 
)
= - 315 J
Thus, we can conclude that the enthalpy of reaction is -315 J.
As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ
where, t1/2 is half-life and λ is the decay constant.
t1/2 = 10 min = 0.693 / λ
Hence, λ = 0.693 / 10 min - (1)
Nt = Nο e∧(-λt)
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken
by rearranging the equation,
Nt/Nο = e∧(-λt) - (2)
From (1) and (2),
Nt/Nο = e∧(-(0.693 / 10 min) x 20 min)
Nt/Nο = 0.2500
Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
= (Nt/Nο ) x 100%
= 0.2500 x 100%
= 25.00%
Hence, Percentage of remaining nuclei is 25.00%
