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PIT_PIT [208]
3 years ago
7

How does helium form (5-8) sentences

Chemistry
1 answer:
Firlakuza [10]3 years ago
7 0
On Earth it is relatively rare—5.2 ppm by volume in the atmosphere. Most terrestrial helium<span> present today is created by the natural radioactive decay of heavy radioactive elements (thorium and uranium, although there are other examples), as the alpha particles emitted by such decays consist of </span>helium<span>-4 nuclei.</span>
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Explanation:

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Which definition best describes the term activation energy?
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B

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Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?​
EastWind [94]

Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

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1 year ago
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Explain how atoms are held together in covalent bonds. Give an example of a covalent compound.
asambeis [7]

Answer:

Explanation:

Atoms are held together by covalent bonds when they share electrons between themselves.

Covalent bonds are bonds that are formed between non-metals usually with a low electronegative difference between them. In this bond type, two non-metals donate electrons which are shared between the combining atoms and this makes them both like the corresponding noble gases. The shared electrons is what forms the covalent bonds.

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5 0
3 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

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