2Al₂O₃ = 4Al + 3O₂
M(A₂O₃)=101.96 g/mol
m(Al₂O₃)=250 g
n(O₂)=3m(Al₂O₃)/{2M(Al₂O₃)}
n(O₂)=3*250/{2*101.96}=3.678 mol
Answer:
2914 J
Explanation:
Step 1: Given data
- Mass of the copper tubing (m): 665.0 g
- Initial temperature: 15.71 °C
- Final temperature: 27.09 °C
- Specific heat of copper (c): 0.3850 J/g.°C
Step 2: Calculate the temperature change
ΔT = 27.09 °C - 15.71 °C = 11.38 °C
Step 3: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.3850 J/g.°C × 665.0 g × 11.38 °C
Q = 2914 J
Answer:
15.99937 is the value of this question answer
