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pashok25 [27]
2 years ago
5

A spring scale hung from the ceiling stretches by 6.1cm when a 2.0kg mass is hung from it. The 2.0kg mass is removed and replace

d with a 2.8kg mass.What is the stretch of the spring?
Physics
1 answer:
Anarel [89]2 years ago
8 0
2.0kg and the mass of sometimes makes it hard 2.8kg
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What is work - energy theorem ??​
Elden [556K]

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

mark me as brainliest ❤️

3 0
2 years ago
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A sound wave travels through water at 1,500 m/s. How far would it travel in 5 s?
hichkok12 [17]
7500m because 1,500 in 1 sec so 1500x5 7500
8 0
2 years ago
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The force between charged objects decreases when their separation ..... A)increase<br> B)decrease
weqwewe [10]
Answer A: When their separation increases.

Hope this helps! :D
6 0
2 years ago
5.3 two 30 kg children in a 20 kg cart are stationary at the top of a hill. They start rolling down the 80 m tall hill and they
Makovka662 [10]

Answer:

<em>60008.4 J</em>

<em></em>

Explanation:

The mass of each kid = 30 kg

mass of the cart = 20 kg

The speed of the cart down the hill = 30 km/hr = 30 x 1000/3600 = 8.33 m/s

The height of the hill = 80 m

The potential energy of the boys at the top of the hill = mgh

where

m is the total mass of the kids and the cart = (30 x 2) + 20 = 80 kg

g is the acceleration due to gravity = 9.81 m/s^2

h is their height above the ground = 80 m (on the top of the hill)

substituting, we have

potential energy PE = 80 x 9.81 x 80 = 62784 J

At an instance at the bottom of the hill

their kinetic energy = \frac{1}{2} mv^2

where

v is their velocity = 8.33 m/s

m is their total mass = 80 kg

substituting, we have

kinetic energy KE = \frac{1}{2}*80*8.33^2 = 2775.6 J

Total work done on the cart is equal to the energy lost by the cart when it reached the bottom of the hill

work done by friction = PE - KE = 62784 - 2775.6 = <em>60008.4 J</em>

5 0
2 years ago
The bar graph shows the population of male and female deer in a forest, measured in 10-year intervals. According to the graph, w
saul85 [17]

Answer: option D. the ratio of the population of male deer is not constant.


Explanation:


The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.


These features are remarkable:


  • The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.

        This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.


  • The population of female deer (purple or brown bars) decreases every decade.

        This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.


  • The populations never are equal, hence this discards the option C.

  • Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
4 0
3 years ago
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