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Akimi4 [234]
3 years ago
11

If a 500kg elephant is sliding across a frictionless patch of ice, how much force is needed to keep the elephant from slowing do

wn?
Physics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

<h3>4905N</h3>

Explanation:

The force needed to keep the elephant from slowing down is expressed as shown according to Newtons second law of motion.

Force = mass * acceleration due to gravity

Given

Mass of elephant = 500kg

acceleration due to gravity = 9.81m/s²

Force = 500*9.81

Force = 4905N

<em>Hence the force needed to keep the elephant from slowing down is 4905N</em>

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The bicyclist accelerates with magnitude <em>a</em> such that

25.0 m = 1/2 <em>a</em> (4.90 s)²

Solve for <em>a</em> :

<em>a</em> = (25.0 m) / (1/2 (4.90 s)²) ≈ 2.08 m/s²

Then her final speed is <em>v</em> such that

<em>v</em> ² - 0² = 2<em>a</em> (25.0 m)

Solve for <em>v</em> :

<em>v</em> = √(2 (2.08 m/s²) / (25.0 m)) ≈ 10.2 m/s

Convert to mph. If you know that 1 m ≈ 3.28 ft, then

(10.2 m/s) • (3.28 ft/m) • (1/5280 mi/ft) • (3600 s/h) ≈ 22.8 mi/h

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3 years ago
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In an inkjet printer, letters and images are created by squirting drops of ink horizontally at a sheet of paper from a rapidly m
Serga [27]

Answer:

q = 6.48 \times 10^{-14} C

Explanation:

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now we know that time to cross the plates is given as

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