All categories

2 years ago

Please show work ela common core 6th grade 1 step equations

Mathematics

2 answers:

horrorfan [7]2 years ago

7 0

Here are the first five:

1) a+3/4=-1/4
a=-1/4-3/4
a=-1

2) c-2/7=8/7
c=8/7+2/7
c=10/7 OR 1 3/7

3) 7/5=g-6/5
7/5+6/5=g
g=13/5 OR 2 3/5

4) 2/3=1/3+k
2/3-1/3=k
1/3=k

5) 5/6=m+1/6
5/6-1/6=m
4/6=m
2/3=m

arlik [135]2 years ago

4 0

Some of the answers are going to be negative fractions, and some are going to be positive. I can't show the work on here right now but I hope that this helped a little bit. If you have any further questions then let me know and I can try to help you!

You might be interested in

A student in Greece discovers a pottery bowl that contains 65% of its original amount of C-14

stira [4]

There isn't enough information to answer

4 0

3 years ago

A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
$\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$
$A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4$

We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

3 0

2 years ago

A combination lock has 25 numbers on it. How many different 3-digit lock combinations are possible if no digit can be repeated?

IgorC [24]

Answer:

The number of ways is 13,800 ways

Step-by-step explanation:

In this question, we are tasked with calculating the number of ways to form 3-digits codes from 25 different numbers given that no repetition is allowed.

Now, for the first digit, we have all the 25 numbers completely wanting to take a spot. Now, in how many ways can we choose a single out of 25, that would be 25 ways

Now, we have 24 numbers left, and we are trying to pick one, the number of ways this can be done is 24 ways also

for the last digit, we have 23 numbers and we are selecting just one, the number of ways this can be done is 23 ways too

Thus, the cumulative number of ways would be 25 * 24 * 23 = 13,800 ways

7 0

2 years ago

Tom bought 2.5 cakes for class for the class picnic. 25 students will share the cake equally. what fractional part of a cake sho

kvv77 [185]

THE ANSWER IS 27.5,BECAUSE WHEN I ADDED IT 25+2.5 I GOT 27.5.THIS IS HOW I GOT MY ANSWER.

7 0

3 years ago

one angle of a triangle has a measure of 66°. the measure of the third angle is 57° more than 1/2 the measure of the second angl

oksano4ka [1.4K]

The third angle is answered in the question. The second angle is 57 degrees.

57+66= 123.

180-123
=57

6 0

2 years ago