I don't think that 4m has anything to do with the problem.
anyway. here.
A___________________B_______C
where A is the point that the train was released.
B is where the wheel started to stick
C is where it stopped
From A to B, v=2.5m/s, it takes 2s to go A to B so t=2
AB= v*t = 2.5 * 2 = 5m
The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m
then BC= AC-AB = 7.7-5 = 2.7m
now consider BC
v^2=u^2+2as
where u is initial speed, in this case is 2.5m/s
v is final speed, train stop at C so final speed=0, so v=0
a is acceleration
s is displacement, which is BC=2.7m
substitute all the number into equation, we have
0^2 = 2.5^2 + 2*a*2.7
0 = 6.25 + 5.4a
a = -6.25/5.4 = -1.157
so acceleration is -1.157m/(s^2)
Answer:
series
Explanation:
In a series circuit all the components are attached to one branch, so that if one component fails, all the others stop working. In a parallel circuit, however, the components are wired in separate branches, so that even if one branch fails, the rest are not disrupted.
Answer:
The RMS voltage across the resistor = 28 V
Explanation:
Capacitor: A capacitor is an electrical device that has the ability to store electrical charges in an electrical circuit. It is expressed in Farad (F)
Resistor: A resistor is an electrical device that oppose the flow of electric current in a circuit. It is expressed in ohms (Ω)
RMS Voltage : RMS voltage value of an alternating voltage is defined as that value of steady voltage which would dissipate heat at the same rate in a given resistance
Since the it is a series circuit, the total voltage is divided across the resistance and the capacitor.
Vt = V₁ + V₂...........................Equation 1
Where Vt = total Rms voltage = 120 V , V₁ = Rms voltage across the Capacitor = 92 V, V₂ = Rms voltage across the resistor.
Making V₂ the subject of the equation in equation 1 above,
V₂ = Vt - V₁ = 120 - 92
V₂ = 28 V.
The RMS voltage across the resistor = 28 V
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Answer:
An object is called a horizontal projectile if it is launched from a certain height with some initial horizontal velocity only. The initial vertical velocity of such an object is zero. But as the object falls through the atmosphere the horizontal component of velocity remains constant but vertical component increases due to gravitational acceleration.
Explanation:
