Answer:
Maximum force, F = 1809.55 N
Explanation:
Given that,
Diameter of the anterior cruciate ligament, d = 4.8 mm
Radius, r = 2.4 mm
The tensile strength of the anterior cruciate ligament, 
We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N
Answer:
Guysi hate math answer this guy plsss ssss
Answer:
This means C.the car uses 20% of the energy store in the gasoline for motion.
Explanation:
I hope this helps.
Answer: A. Her speed is 4.4 m/s, and her velocity is 0 m/s.
Explanation: i took the test on edgenuity