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Lemur [1.5K]
2 years ago
15

The gravitational force between two objects is represented by the variable F.

Physics
1 answer:
Korolek [52]2 years ago
5 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between both objects.

now, we change these numbers

Fgravitynew = G*(2*mass1*2*mass2)/(1/2 * D)² =

= G*(4*mass1*mass2)/(D²/4) =

= 4* (G*(mass1*mass2)/D²) *4 =

= 16* (G*(mass1*mass2)/D²) = 16*Fgravity

so, the new gravitational force will be 16×F.

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Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).

Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).

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3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

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a_{min} = \dfrac{mg }{ \mu_s m}

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where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

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If one stand of DNA reads as AATTCCGGATCG, what would the opposite strand bases be?
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