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Nataliya [291]
3 years ago
6

An object weighing 1.840 kg has a volume of 0.0015 m3. What is the density of the object in g/cm3?

Physics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

1.22gcm³

Explanation:

D = mass/ volume

Mass=1.840kg = 1,840g

1000g = 1kg

1.840kg= x(g)

X(g) = 1.840/1000

= 1840g

Volume = 0.0015m³= 1,500cm³

1m³= 1000,000cm³.

0.0015m³= x(cm³)

X(cm³) = 1000,000×0.0015

X(cm³)= 1500.

Since density is mass/volume, now impute your data's

D=m/v

D=1840/1500

1.22g/cm³

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Answer:

197.2 m/s^2

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

a=\omega^2 r

where

\omega is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

f=\frac{5}{1}=5 Hz

and the angular velocity is

\omega=2\pi f = 2\pi (5)=31.4 rad/s

While the distance of the point from the axis of rotation is

r=0.20 m

Substituting, we find the acceleration:

a=(31.4)^2(0.20)=197.2 m/s^2

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3 years ago
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A cyclist intends to cycle up a 7.70o hill whose vertical height is 126m. Assuming the mass of bicycle plus person is 75.0kg, ca
Ksivusya [100]

Answer:

92704.5 J

596.44737 N

Explanation:

m = Mass of person + bicycle = 75 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical height = 126 m

\theta = Angle = 7.7°

d = Diameter = 0.388 m

Work done against gravity is given by

P=mgh\\\Rightarrow P=75\times 9.81\times 126\\\Rightarrow P=92704.5\ J

Work done is 92704.5 J

Force required is given by

F=\dfrac{mgrsin\theta}{\pi d}\\\Rightarrow F=\dfrac{75\times 9.81\times sin7.7\times 5.12}{\pi\times 0.388}\\\Rightarrow F=596.44737\ N

The force is 596.44737 N

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3 years ago
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Katie claims that steel is a homogeneous mixture, even though it looks like a
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Answer:

D. Steel is made of different compounds distributed unevenly.

Explanation:

The statement that will support her claim that steel is a homogenous mixture is that steel is made up of different compounds distributed unevenly.

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  • Alloys are classified as mixtures.
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3 years ago
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A 1.0 kg object is attached to a string 0.50 m. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s.
zysi [14]

Answer: d

Explanation:

For an object to move in a uniform circular motion, only force that acts on it is the centripetal force which acts along the line joining the object and center of the circular path. The acceleration also acts in the direction of force. The centripetal acceleration acts along the radius of the circular motion path.

In the given horizontal circle, the direction of the acceleration of the object points towards d.

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