Answer:
1561.84 MPa
Explanation:
L=20 cm
d1=0.21 cm
d2=0.25 cm
F=5500 N
a) σ= F/A1= 5000/(π/4×(0.0025)^2)= 1018.5916 MPa
lateral strain= Δd/d1= (0.0021-0.0025)/0.0025= -0.16
longitudinal strain (ε_l)= -lateral strain/ν = -(-0.16)/0.3
(assuming a poisson's ration of 0.3)
ε_l =0.16/0.3 = 0.5333
b) σ_true= σ(1+ ε_l)= 1018.5916( 1+0.5333)
σ_true = 1561.84 MPa
ε_true = ln( 1+ε_l)= ln(1+0.5333)
ε_true= 0.4274222
The engineering stress on the rod when it is loaded with a 5500 N weight is 1561.84 MPa.
Answer:
The source code files for this question have been attached to this response.
Please download it and go through each of the class files.
The codes contain explanatory comments explaining important segments of the codes, kindly go through these comments.
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
2,000 the answer __________im Shayla_________I like food _________do you________the crunch for me_______km not fat tho______are u no worrys________is u are u still pretty
Explanation:
McLeod gauge:
It is used to measure very low pressure of gas.It measure gas pressure by the help of mercury(Hg).it measure absolute pressure of gas.
McLeod gauge on the principle of Boyle's law.Boyle's law state that ,at constant temperature the pressure of gas is directly proportional to its volume.From Boyle's law
A sample of gas is taken from vacuum then its pressure is measured by help Hg.
