Answer:
moles O₂ needed = 0.19 mole
Explanation:
4Fe(s) + 3O₂(g) => 2Fe₂O₃(s)
1.396g Fe(s) = 1.396g/56g/mol = 0.025 mole Fe(s)
0.025 mole Fe(s) reacts with 3/4(0.025 mole O₂(g) = 0.019 mole O₂(g)
Answer:
c.Elements in the compound shares electrons
Explanation:
Because in ionic compounds element lose or gain electrons only
Sharing of electrons is the property of covlant compounds.
Answer:
\large \boxed{\text{150 g TiCl}_{4}}
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 189.68 79.87
TiCl₄ + 2H₂O ⟶ TiO₂ + 4HCl
m/g: 50.0
To solve this stoichiometry problem, you must
- Convert the actual yield to the theoretical yield
- Use the molar mass of TiO₂ to convert the theoretical yield of TiO₂ to moles of TiO₂
- Use the molar ratio to convert moles of TiO₂ to moles of TiCl₄
- Use the molar mass of TiCl₄ to convert moles of TiCl₄ to mass of TiCt₄
1. Theoretical yield of TiO₂

2. Moles of TiO₂

3, Moles of TiCl₄
The molar ratio is 1 mol TiO₂:1 mol TiCl₄.

4. Mass of TiCl₄

Answer:
The percentage of the block contains 15% after 60 years.
Explanation:
Step 1: Formula for half-life time
To calculate the half-life time we will use the following formula:
At = A0 * 1/2 ^(x/t)
With At = the quantity after a time t
A0 = The quantity at time t = 0 (start)
x = time in this case = 60 years
t= half-life time = 22 years
Step 2: Calculate the percentage after 60 years
In this case: after 60 years the percentage will be
A0= 10 * 1/2 ^(60/22)
A0 = 1.5
A0 / At = 1.5 /10 = 0.15
0.15 *100% = 15 %
The percentage of the block contains 15% after 60 years.
Glycine: Yes.
Dextrose: No.
Hope this helps! (: