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11Alexandr11 [23.1K]
3 years ago
13

HELP!!! can anyone tell me if this virtual titration lab is right & help me find the missing concentrations ??

Chemistry
2 answers:
kow [346]3 years ago
6 0
The equation that you need to use is M₁V₁=M₂V₂ for both cases since the molar ratio is 1.

In titration 1:
You would use the equation M₂=M₁V₁/V₂

M₁=concentration of NaOH (0.1M)
V₁=volume of NaOH added (16mL)
V₂=volume of HCl in the Erlenmeyer flask (20mL) 
M₂=concentration of HCl in the Erlenmeyer flask (unknown)

M₂=(0.1M*16mL)/20mL
M₂=0.08M
The concentration of acid was 0.08M

Titration 2:
Still use the formula M₂=M₁V₁/V₂

M₁=concentration of HCL (0.1M)
V₁=volume of HCl added (14mL)
V₂=volume of NaOH in Erlenmeyer flask (20mL)
M₂=concentration of NaOH in the Erlenmeyer flask (unknown)

M₂=(0.1M*14mL)/20mL
M₂=0.07M
concentration of the NaOH is 0.07M

I hope this helps.  Let me know if you have any further questions or if anything needs to be clarified.
malfutka [58]3 years ago
3 0
Concentration is wrong, conc=moles/volume, both concentration are wrong use the formula to correct it.
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Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

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Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

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Explanation:

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if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

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So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

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in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

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