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3 years ago

9

Which of the following is NOT an area of study in chemistry? * 1 point Biochemistry Physical chemistry Ergonomic chemistry Analy

tical chemistry

2 answers:

artcher [175]3 years ago

5 0

Answer:

i can't see it

Explanation:

wish i could help

USPshnik [31]3 years ago

4 0

Answer:

bio physical chemist

Explanation:

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How many valence electrons does oxygen have?<br> A. 2<br> B. 6<br> C. 8<br> D. 16

AleksandrR [38]

Oxygen has 6 valence electrons, so B

8 0

3 years ago

4. Consider the following statement made in Chapter 4 of the text: "... consider that if the

AveGali [126]

The claim: "If the nucleus were the size of a grape, the electrons would be one mile away on average" is reasonably accurate because the ratios between the nucleus's sizes and the distances (between electrons and nucleus) for the two given examples are in the same order of magnitude.

To know if the claim is accurate we need to calculate the ratio of the size of the nucleus (the same as a grape) and the distance between the electrons and the nucleus for example 1 (r₁):

$r_{1} = \frac{s_{1}}{d_{1}}$ (1)

and to compare it with the ratio of the size and the distance given in example 2 (r₂):

$r_{2} = \frac{s_{2}}{d_{2}}$ (2)

<em>Where:</em>

s₁: is the size of the nucleus (like the size of a grape)

d₁: is the distance between electrons and nucleus of example 1 = 1 mile

s₂: is the average diameter of the nucleus = 10⁻¹³ cm

d₂: is the average distance between electrons and nucleus of example 2 = 10⁻⁸ cm

Assuming that the diameter of a grape is 3 cm (in a spherical way), the ratio of the <u>first example</u> is (eq 1):

$r_{1} = \frac{3 cm}{1 mi*\frac{160934 cm}{1 mi}} = 1.86 \cdot 10^{-5}$

Now, the ratio of the <u>second example</u> is (eq 2):

$r_{2} = \frac{10^{-13} cm}{10^{-8} cm} = 1.00 \cdot 10^{-5}$

Since r₁ and r₂ are in the same order of magnitude (10⁻⁵), we can conclude that the given claim is reasonably accurate.

You can learn more about the nucleus of an atom here: brainly.com/question/10658589?referrer=searchResults

I hope it helps you!

3 0

3 years ago

In a neutralization reaction with a strong acid or base, all of the hydrogens from the acid and the hydroxides from the base rea

masya89 [10]

Answer:

H3PO4 + 3NaOH ----> Na3PO4 + 3H2O

Explanation:

The balanced equation is given below

H3PO4 + 3NaOH ----> Na3PO4 + 3H2O

7 0

3 years ago

Read 2 more answers

Calculate the wavelength in nm of ultraviolet light with frequency of 5.5 x 10¹⁵ Hz.

snow_tiger [21]

Answer: Wavelength of ultraviolet light is 54 nm.

Explanation:

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light.

The relationship between wavelength and frequency of the wave follows the equation:

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of the wave = $5.5\times 10^{15}Hz$

c = speed of light = $3\times 10^8ms^{-1}$

$\lambda$ = wavelength of the wave

Putting in the values we get:

$5.5\times 10^{15}s^{-1}=\frac{3\times 10^8ms^{-1}}{\lambda}$

$\lambda=0.54\times 10^{-7}m$

$1nm=10^{-9}m$

$\lambda=54nm$

Thus wavelength of ultraviolet light is 54 nm.

6 0

3 years ago

On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What

topjm [15]

Answer : The atomic mass of chlorine is, 36.723 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Mass of 35-Cl isotope = 35 amu

Percentage abundance of 35-Cl isotope = 13.85 %

Fractional abundance of 35-Cl isotope = 0.1385

Mass of 37-Cl isotope = 37 amu

Percentage abundance of 37-Cl isotope = 86.15 %

Fractional abundance of 37-Cl isotope = 0.8615

Now put all the given values in above formula, we get:

$\text{Average atomic mass }=[(35\times 0.1385)+(37\times 0.8615)]$

$\text{Average atomic mass }=36.723amu$

Therefore, the atomic mass of chlorine is, 36.723 amu

6 0

4 years ago