Answer:
3.2 g of O₂
Solution:
This reaction is for the formation of Potassium Superoxide, The reaction is as follow,
K + O₂ → KO₂
First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
39.098 g (1 mole) K produced = 71.098 g of K₂O
So,
3.91 g of K will produce = X g of K₂O
Solving for X,
X = (3.91 g × 71.098 g) ÷ 39.098
X = 7.11 g of K₂O
Hence, it is confirmed that we have selected the right equation,
So,
As,
39.098 g of K required = 32 g of O₂
So,
3.91 g of K will require = X g of O₂
Solving for X,
X = (3.91 g × 32 g) ÷ 39.098 g
X = 3.2 g of O₂
Answer:
1) HNO3/H2SO4, 2) CH3CH2CH2Cl/AlCl3
Explanation:
Benzene is a stable aromatic compound hence it undergoes substitution rather than addition reaction.
When benzene undergoes substitution reaction, the substituent introduced into the ring determines the position of the incoming electrophile.
If I want to synthesize m-nitropropylbenzene, I will first carry out the nitration of benzene using HNO3/H2SO4 since the -nitro group is a meta director. This is now followed by Friedel Craft's alkykation using CH3CH2CH2Cl/AlCl3.
When two atoms of Florine combines, they share an electron pair to complete it's octet. This result is formation of single bond between two fluorine atoms. This process is exothermic in nature, and hence, heat is liberated during the process of bond formation. <span />
The grams of NaCl that are required to make 150.0 ml of a 5.000 M solution is 43.875 g
calculation
Step 1:calculate the number of moles
moles = molarity x volume in L
volume = 150 ml / 1000 = 0.15 L
= 0.15 L x 5.000 M = 0.75 moles
Step 2: calculate mass
mass = moles x molar mass
molar mass of NaCl = 23 + 35.5 = 58.5 mol /L
mass is therefore =0.75 moles x 58.5 mol /l =43.875 g
