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dybincka [34]
3 years ago
7

Solve. −4.2y+2.1>−2.52 Drag and drop a number or symbol into each box to show the solution.

Mathematics
1 answer:
Daniel [21]3 years ago
6 0
Given problem is -4.2y+2.1>-2.52.
To solve this, we combine numbers by transposing -2.52 to the left side and transposing variable term in the right side as shown below:
2.1+2.52>4.2y
Perform addition of values 2.1 and 2.52, 
4.62>4.2y
Then, divide both sides with 4.2 and the result is 1.1>y.
The answer is y<1.1.


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Use the Associative Property to find the value of the variable.<br> (8 x 15) x s = 8 x (15 x 11)
kvasek [131]

Answer:

hey its me again so the answer is 11.

I'm sure because I did this.

5 0
1 year ago
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Ymorist [56]

the answer for this question is (B) 5,-2

7 0
3 years ago
Are the marks one receives in a course related to the amount of time spent studying the subject? To analyze this mysterious poss
sertanlavr [38]

Answer:

a) 98.522

b) 0.881

c) The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time.

Step-by-step explanation:

a.

As the mentioned in the given instruction the co-variance is first computed in excel by using only add/Sum, subtract, multiply, divide functions.

Marks y Time spent x y-ybar x-xbar (y-ybar)(x-xbar)

77                    40 5.1         1.3 6.63

63                     42 -8.9            3.3 -29.37

79                     37 7.1            -1.7 -12.07

86                     47 14.1            8.3 117.03

51                    25 -20.9  -13.7 286.33

78                     44 6.1            5.3 32.33

83                      41 11.1            2.3 25.53

90                     48 18.1            9.3 168.33

65                     35 -6.9           -3.7 25.53

47                    28 -24.9 -10.7 266.43

Covariance=\frac{sum[(y-ybar)(x-xbar)]}{n-1}

Co-variance=886.7/(10-1)

Co-variance=886.7/9

Co-variance=98.5222

The co-variance computed using excel function COVARIANCE.S(B1:B11,A1:A11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted co-variance is 98.52222.

b)

The correlation coefficient is computed as

Correlation coefficient=r=\frac{sum[(y-ybar)(x-xbar)]}{\sqrt{sum[(x-xbar)]^2sum[(y-ybar)]^2} }

(y-ybar)^2 (x-xbar)^2

26.01        1.69

79.21       10.89

50.41             2.89

198.81       68.89

436.81       187.69

37.21       28.09

123.21        5.29

327.61        86.49

47.61         13.69

620.01         114.49

sum(y-ybar)^2=1946.9

sum(x-xbar)^2=520.1

Correlation coefficient=r=\frac{886.7}{\sqrt{520.1(1946.9)} }

Correlation coefficient=r=\frac{886.7}{\sqrt{1012582.69} }

Correlation coefficient=r=\frac{886.7}{1006.2717 }

Correlation coefficient=r=0.881

The correlation coefficient computed using excel function CORREL(A1:A11,B1:B11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted correlation coefficient is 0.881.

c)

The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time. It means that as the study time increases the marks of student also increases and if the study time decreases the marks of student also decreases.

The excel file is attached on which all the related work is done.

Download xlsx
7 0
3 years ago
Find the range of the following piecewise function.
Anna11 [10]

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

End value: f(3)=3+4=7

Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

5 0
2 years ago
A computed measure of how much scores vary around the mean score
Paladinen [302]
That's called <span>standard deviation.

Hope this helps !

Photon</span>
5 0
3 years ago
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