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agasfer [191]
3 years ago
10

Plz help! :) :D I will mark you as BRAINLIEST!!!

Chemistry
1 answer:
nadezda [96]3 years ago
8 0

Answer:

Some of the physical and chemical properties of magnesium are:

-The term ‘magnesium’ is derived from the Greek word magnesia, which refers to the name of the place from where it was extracted.

-Magnesium is closely related to manganese and magnetite.

-About 2.1% of the Earth’s crust contains magnesium. This makes magnesium the 6th most found element.

-The biggest deposits of magnesium is found in the seawater. It has been calculated by scientists that a cubic mile of seawater contains about 6 million tons of this element

2nd answer:

Physical Properties of Magnesium: ”I’m a highly stable element, so you can count on me”

Chemical Properties of Magnesium: ”I love to travel but I do corrode aluminum so we won’t be flying off on adventures in airplanes planes anytime soon

Explanation:

Hope this helps you out! UwU

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According to the equation below, how many moles of Ca(OH)2 are required to react with 1.36 mol H3PO4 to produce Ca3(PO4)2? 3Ca(O
allsm [11]

<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles

<u>Explanation:</u>

We are given:

Moles of phosphoric acid = 1.36 moles

For the given chemical equation:

3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O

By Stoichiometry of the reaction:

2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide

So, 1.36 moles of phosphoric acid will react with = \frac{3}{2}\times 1.36=2.04mol of calcium hydroxide

Hence, the amount of calcium hydroxide needed to react is 2.04 moles

3 0
3 years ago
Un tecnico di laboratorio deve preparare una soluzione di carbonato di sodio decaidrato, Na2CO3⋅ 10 H2O per eseguire alcune anal
fiasKO [112]

Answer:

1.  3.70 g Na₂CO₃·10H₂O

2. 50.0 mL of the first solution

Explanation:

1. Prepare the solution

(a) Calculate the molar mass of Na₂CO₃·10H₂O

\begin{array}{rrr}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 2\times22.99 & 45.98\\\text{1C} & 1\times 12.01 & 12.01\\\text{13O}&13 \times16.00 & 208.00\\\text{20H}&20 \times 1.008 & 20.16\\&\text{TOTAL =} & \mathbf{286.15}\\\end{array}

The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.

(b) Calculate the moles of Na₂CO₃·10H₂O

\text{Moles of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\= \text{0.250 L solution} \times \dfrac{\text{0.0500 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 L solution}}\\\\= \text{0.0125 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

(c) Calculate the mass of Na₂CO₃·10H₂O

\text{Mass of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O }\\= \text{0.012 50 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O } \times \dfrac{\text{296.15 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}\\\\= \text{3.70 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\\text{You need $\large \boxed{\textbf{3.70 g}}$ of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

2. Dilute the solution

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = ?;            c₁ = 0.0500 mol·L⁻¹

V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹

Calculation:

\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\V_{1}\times \text{0.0500 mol/L} & = & \text{100 mL} \times\text{0.0250 mol/L}\\0.0500V_{1}& = & \text{2.500 mL}\\V_{1}&=& \dfrac{\text{2.500 mL}}{0.0500}\\\\& = &  \text{50.0 mL}\\\end{array}\\\text{You need $\large \boxed{\textbf{50.0 mL}}$ of the concentrated solution.}

7 0
3 years ago
The solubility of k2cr2o7 in water is 125 g/l at 20 °c. a solution is prepared at 20 °c that contains 6.0 grams of k2cr2o7 in 50
Pachacha [2.7K]
The solubility is the guide to the maximum amount of solute that can be dissolved in a certain amount of solvent at a certain temperature to make a saturated solution. Any amount less than this would result to unsaturated, while any amount more would result to saturated.

6 g/(50 mL * 1 L/1000 mL) = 120 g/L

Since it is less than the solubility of 125 g/L, then <em>this solution is unsaturated</em>.
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1. A fluid is a substance that (a) always expands until it fills any container; (b) is practically incompressible; (c) cannot be
meriva

Answer:

cannot remain at rest under the action of any shear force.

4 0
1 year ago
A pulse with an amplitude of 3+ would be considered:
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4 0
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