The answer is D, talking more loudly or quietly.
<span>
An expressive voice can bring totally different meaning to what you are saying. If you speak in a monotone voice, you are implying that you do not care about what you are saying or what the other person is talking about. If you speak expressively with some parts quieter or louder to make a point, it lets the listener know that you care about what you are saying and you care about what they have to say too. You can also emphasize a point by speaking louder or indicate that something is not as important by speaking softer.</span>
r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC
Answer:0.6
Explanation:
Given
Bowl contains 4 red and 2 Green balls
Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1
Probability of selecting two red balls given that no ball is red ![=\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BProbability%20%5C%20of%5C%20selecting%5C%20two%5C%20red%5C%20balls%5C%20out%5C%20of%5C%204%5C%20balls%7D%7Bprobability%5C%20of%5C%20selecting%5C%202%5C%20balls%5C%20out%5C%20of%5C%206%20balls%7D)
![P=\frac{^{4}C_2}{^{6}C_2}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B%5E%7B4%7DC_2%7D%7B%5E%7B6%7DC_2%7D)
![P=\frac{2}{5}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2%7D%7B5%7D)
Required Probability![=1-\frac{2}{5}=\frac{3}{5}](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7B2%7D%7B5%7D%3D%5Cfrac%7B3%7D%7B5%7D)
Answer:
Time, t = 0.015 seconds.
Explanation:
Given the following data;
Mass, m = 0.2kg
Force, F = 200N
Initial velocity, u = 40m/s
Final velocity, v = 25m/s
To find the time;
Ft = m(v - u)
Time, t = m(v - u)/f
Substituting into the equation, we have;
Time, t = 0.2(25 - 40)/200
Time, t = 0.2(-15)/200
Time, t = 3/200
Time, t = 0.015 seconds.
Note: We ignored the negative sign because time can't be negative.