Question

If x=12 in, y=16, and z=20 in, what is the surface area of the geometric shape formed by this net?

Answer 1

Given:

x = 12 in, y = 16 in and z = 20 in

To find:

The surface area of the geometric shape.

Solution:

Area of top rectangle = z × z

                                    = 20 × 20

Area of top rectangle = 400 in²

Area of middle rectangle = z × y

                                          = 20 × 16

Area of middle rectangle = 320 in²

Area of bottom rectangle = z × x

                                          = 20 × 12

Area of bottom rectangle = 240 in²

Area of left triangle = $\frac{1}{2}yx$

                                $=\frac{1}{2}\times16\times12$

Area of left triangle = 96 in²

Area of right triangle = $\frac{1}{2}yx$

                                $=\frac{1}{2}\times16\times12$

Area of right triangle = 96 in²

Surface area = 400 + 320 + 240 + 96 + 96

                     = 1152

The surface area of the geometric shape is 1152 in².