If x=12 in, y=16, and z=20 in, what is the surface area of the geometric shape formed by this net?
1 answer:
Given:
x = 12 in, y = 16 in and z = 20 in
To find:
The surface area of the geometric shape.
Solution:
Area of top rectangle = z × z
= 20 × 20
Area of top rectangle = 400 in²
Area of middle rectangle = z × y
= 20 × 16
Area of middle rectangle = 320 in²
Area of bottom rectangle = z × x
= 20 × 12
Area of bottom rectangle = 240 in²
Area of left triangle =
Area of left triangle = 96 in²
Area of right triangle =
Area of right triangle = 96 in²
Surface area = 400 + 320 + 240 + 96 + 96
= 1152
The surface area of the geometric shape is 1152 in².
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Answer:
Step-by-step explanation:
There are 3 ways to find the other x intercept.
1) Polynomial Long Division.
Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.
2) Just solving for x when y = 0, by using the quadratic formula.
.
So the other x - intercept is at (1, 0)
3) Using Vietta's Theorem regarding the solutions of a quadratic
Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.
And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.
These relations between the solutions give us a brief idea of what the solutions should be like.