Well, let's take a peek at the graph of that line, hmmm let's pick two points, heck, those tow on the extremes anyway, and those are (-5,2) and (5,-1), alrite.. now, let's do some checking on that.
![\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=-\cfrac{3}{10}[x-(-5)] \\\\\\ y-2=-\cfrac{3}{10}(x+5)\implies y-2=-\cfrac{3}{10}x-\cfrac{3}{2}\implies y=-\cfrac{3}{10}x-\cfrac{3}{2}+2 \\\\\\ y=-\cfrac{3}{10}x+\cfrac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%7B%7B%20y_1%7D%7D%3D%7B%7B%20m%7D%7D%28x-%7B%7B%20x_1%7D%7D%29%7D%5Cimplies%20y-2%3D-%5Ccfrac%7B3%7D%7B10%7D%5Bx-%28-5%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-2%3D-%5Ccfrac%7B3%7D%7B10%7D%28x%2B5%29%5Cimplies%20y-2%3D-%5Ccfrac%7B3%7D%7B10%7Dx-%5Ccfrac%7B3%7D%7B2%7D%5Cimplies%20y%3D-%5Ccfrac%7B3%7D%7B10%7Dx-%5Ccfrac%7B3%7D%7B2%7D%2B2%0A%5C%5C%5C%5C%5C%5C%0Ay%3D-%5Ccfrac%7B3%7D%7B10%7Dx%2B%5Ccfrac%7B1%7D%7B2%7D)
If x=12 in, y=16, and z=20 in, what is the surface area of the geometric shape formed by this net?
1 answer:
Given:
x = 12 in, y = 16 in and z = 20 in
To find:
The surface area of the geometric shape.
Solution:
Area of top rectangle = z × z
= 20 × 20
Area of top rectangle = 400 in²
Area of middle rectangle = z × y
= 20 × 16
Area of middle rectangle = 320 in²
Area of bottom rectangle = z × x
= 20 × 12
Area of bottom rectangle = 240 in²
Area of left triangle =
Area of left triangle = 96 in²
Area of right triangle =
Area of right triangle = 96 in²
Surface area = 400 + 320 + 240 + 96 + 96
= 1152
The surface area of the geometric shape is 1152 in².
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