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liraira [26]
3 years ago
13

A power plant uses 365 GJ/hr of energy from a boiler and extracts 18 GJ/hr as work from a turbine and rejects the remaining ener

gy to a large cold resevoir of air (the atmosphere). What is the rate of heat rejection to the atmosphere for this plant? Give your answer in GJ/hr
Physics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

The rate of heat rejection will be 347 GJ/hr

Explanation:

We have given that power plant uses energy of 365 GJ/hr

So energy uses Q_B=365GJ/hr

Work done from turbine W_T=18GJ/hr

We have to find the rate of heat rejection to the atmosphere Q_C

We know that Q_B=W_T+Q_C

365=18+Q_C

Q_C=347GJ/hr

So the rate of heat rejection will be 347 GJ/hr

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