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3 years ago

Would a 500 μF or 100 μF capacitor keep a light bulb on longer? Explain your reasoning

Physics

1 answer:

balandron [24]3 years ago

5 0

Answer:

The 500 would be able to keep a light bulb on longer.

Explanation:

The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.

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A 7.5kg block is sliding down a wall with constant velocity. The coefficient of static friction between the block and the wall

weqwewe [10]

Ok, a couple of things have to be accounted for here. First, since the block is moving relative to the wall we have to use the kinetic coefficient of friction, 0.40. The second consideration is that since the block is moving at a constant velocity, the acceleration is zero. This means, by Newton's second Law, that the net force is zero. So the force of gravity must be equal to the friction force of the wall resisting its fall. This friction force is the product of the normal force (which we are seeking) and the kinetic coefficient of friction. We can then set these two forces equal:

$F_{gravity}=mg \\ \\ F_{friction}=F_{norm} \mu_k \\ \\ mg=F_{norm} \mu_k \\ \\ F_{norm}= \frac{mg}{ \mu_k} \\ \\ F_{norm}= \frac{7.5(9.79)}{0.4}=183.6N$

8 0

4 years ago

A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the bod

Leviafan [203]

Answer:

36 J

Explanation:

Let's start off with the Kinetic Energy formula: 1/2m $v^{2}$

So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.

*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.

If 6 kg is the MASS:

Beginning: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2 = $\frac{1}{2}$ (6)(2 squared)= $\frac{1}{2}$ (6)(4)= 12 J

End: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2= $\frac{1}{2}$ (6)(4 squared)= $\frac{1}{2}$ (6)(16)= 48 J

Answer:

36 J

If 6 kg is the WEIGHT:

We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:

Weight = mass x acceleration due to gravity

6 = mass x 9.8

6 = 9.8m

*Divide both sides*

mass = 0.6 kg

Now, we can use the mass to find the kinetic energy.

Beginning: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2 = $\frac{1}{2}$ (0.6)(2 squared)= $\frac{1}{2}$ (0.6)(4)= 1.2 J

End: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2= $\frac{1}{2}$ (0.6)(4 squared)= $\frac{1}{2}$ (0.6)(16)= 4.8 J

Answer:

3.6 J

(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)

4 0

3 years ago

How do they make pickle sunflower seeds?

Kobotan [32]

Preheat oven to 350°F. Spray large baking sheet with cooking spray.

Place dill, garlic powder, onion powder, salt, sugar and ascorbic acid in small bowl and stir to combine.

Generously season sunflower seeds with dill mixture and toss to combine. Taste and season again, if needed.

Arrange seeds on baking sheet and transfer to oven to brown for 10 to 15 minutes, tossing every 5 minutes to prevent burning.

Remove from oven, let cool and store in airtight container.

7 0

3 years ago

Read 2 more answers

A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect a

pochemuha

Answer:

V=14

Explanation:

PE=KE

mgh=1/2mv^2

2(9.8)10=1/2(2)v^2

(radical) 196= (radical)v

V=14

7 0

3 years ago

Wall-E the robot is resting when he randomly explodes into two pieces that fly off in opposite directions. His head has a mass o

Brut [27]

Answer:

The body flies off to the left at 9.1 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If a collision occurs and the velocities change to v', the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\qquad\qquad[1]$

Wall-E robot is initially at rest, its two parts together. His head has a mass of m1=0.75 kg and his body has a mass of m2=6.2 kg. Both parts have initial speeds of zero v1=v2=0.

After the explosion, his head flies off to the right at v1'=75 m/s. We are required to find the speed of his body v2'. Solving [1] for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting values:

$\displaystyle v'_2=\frac{0.75*0+6.2*0-0.75*75}{6.2}$

$\displaystyle v'_2=-9.1 \ m/s$

The body flies off to the left at 9.1 m/s

3 0

3 years ago