The rate of energy absorption from the outdoor air is 4400 KJ/h
<u>Explanation:</u>
Coefficient of performance (COP), is an expression of the efficiency of a heat pump. When calculating the COP for a heat pump, the heat output from the condenser (Q) is compared to the power supplied to the compressor (W).
The coefficient of performance,
We replace the value in the equation with given data,
By making a conversion, we get
The energy balance,
Now, replace the values in the equation, we get
As the room becomes warmer, the temperature of the thermistor will increase as well. The resistance of thermistors reduces when their temperature increases; thus, the current to the motor will increase and the fan will run faster when temperature is increased.
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.
Answer:
The tension in the string at that point is 90.75 N
Explanation:
Given;
mass of the object, m = 3 kg
length of string, r = 0.25 m
the angular velocity, ω = 11 rad/s
The tension on string can be equated to the centrifugal force on the object;
T = mω²r
Where;
T is the tension in the string
m is mass of the object
ω is the angular velocity
r is the radius of the circular path
T = 3 x (11)² x 0.25
T = 90.75 N
Therefore, the tension in the string at that point is 90.75 N
Ohm's Law<span> deals with the relationship between voltage and current in an ideal conductor. </span>Ohm's law<span> states that the current through a conductor between two points is directly proportional to the voltage across the two points. </span>