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3 years ago

13

How many moles are there in 3.612 x 1024 formula units of Na2SO4?

1 answer:

vitfil [10]3 years ago

5 0

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{3.612 \times {10}^{24} }{6.02 \times {10}^{23} } \\$

We have the final answer as

<h3>6 moles</h3>

Hope this helps you

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Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient

romanna [79]

Answer:

Coefficient of $H^{+}(aq)$ is more than 4

Explanation:

Oxidation: $Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)$

Balance charge: $Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)$ ......(1)

Reduction: $Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)$

Balance Cr: $Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)$
Balance O and H in acidic medium: $Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)$
Balance charge: $Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)$ .......(2)

$[3\times Equation-(1)]+Equation(2)$ gives balanced equation:

$3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)$

So coefficient of $H^{+}(aq)$ is more than 4

3 0

3 years ago

Refer to the following unbalanced equation:

user100 [1]

Mass of Oxygen (O₂) : = 88.16 g

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

C₆H₁₄+ O₂ → CO₂ + H₂0

25 g C₆H₁₄

Required

mass of oxygen (O₂)

Solution

Balanced equation

2C₆H₁₄ + 19O₂ ⇒12 CO₂ + 14 H₂O

mol C₆H₁₄ (MW=86,18 g/mol) :

= mass : MW

= 25 g : 86.18 g/mol

= 0.29

From the equation, mol ratio of C₆H₁₄ : O₂ = 2 : 19, so mol O₂ :

= 19/2 x mol C₆H₁₄

= 19/2 x 0.29

= 2.755

Mass O₂(MW=32 g/mol) :

= 2.755 x 32

= 88.16 g

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Explanation:

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Answer:

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