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mafiozo [28]
3 years ago
10

You have a perfectly circular apple pie with a radius of 15cm. You cut the pie into 12 approximately equal slices. What is the a

rc length (linear length) and angular displacement of each slice's crust?
Physics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

7.85 cm

30 degree

Explanation:

As we know that that the angular displacement in one turn is 360 degree.

As there are 12 parts which are equally divided so the angle turn by each part is

= 360 / 12 = 30 degree

Thus, the angular displacement of each slice is 30 degree.

Radius of pie = 15 cm

Circumference of pie = 2 x 3.14 x 15 = 94.2 cm

Arc length for complete 360 degree = 94.2 cm

Arc length for 30 degree turn = 94.2 x 30 / 360 = 7.85 cm

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Answer:

The answer  is The acceleration is double its original value.

Explanation:

<h2><u>It is because of the second trial of accelaration. Because of this, an object's acceleration doubles from its original value.</u></h2><h2><u></u></h2>

Hope this helps....

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6 0
3 years ago
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A person's speed around the Earth is faster at the poles than it is at the equator.
VashaNatasha [74]

Answer:

no

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it is faster at the equator

6 0
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An 85-kg refrigerator is located on the 70th floor of a skyscraper (4km above the ground ) what is the potential energy
Airida [17]
Potential energy can be calculated using the following rule:
potential energy = mgh where:
m is the mass = 85 kg
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Substitute in the above equation to get the potential energy as follows:
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7 0
3 years ago
A 0.5 kg stone is raised from 1m to 2m height from the ground. what is the change in potential energy of the stone?
Usimov [2.4K]

Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

Acceleration due to gravity (g) = 9.8 m/s²

To find: The change in potential energy of the stone

Formula: The potential energy (P) = mgh

where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

Δ P = P₂ - P₁ = mg (h₂ - h₁)

or,                = 0.5 kg ×9.8 m/s² ×(2.0 m - 1.0 m)

or,                = 4.9 J

Hence, the required change in the potential energy of the stone will be 4.9 J

4 0
3 years ago
A force of 9 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then imme
mart [117]

Answer:

\frac{d^2x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0

Explanation:

let m be the mass attached, let k be the spring constant and let \beta be the positive damping constant.

-By Newton's second law:

m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}

where x(t) is the displacement from equilibrium position. The equation can be transformed into:

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