The capacitor is a device that can store electrical energy. It is a two-conductor configuration. The charge on each plate of the capacitor will be 3.6 µC.

<h3>What is a capacitor?</h3>

A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.

An electric insulator or vacuum, such as glass, paper, air, or a semi-conductor termed a dielectric, can be used as the non-conductive zone.

The given data in the problem is;

C is the capicitence of capicitor= 0. 40 µF

V is the voltage = 9. 0 V

Q is a charge on each plate of the capacitor=?µC.

The formula for the capacitor is given as;

$\rm Q=CV \\\\ \rm Q=0. 40 \times 9. 0 \\\\ \rm Q=3.6 \ \mu C.$

Hence the charge on each plate of the capacitor will be 3.6 µC.

To learn more about the capacitor refer to the link;

brainly.com/question/14048432

4 0

3 years ago

Determine the work done by 2. 00 kg of water when it is all boiled to steam at 100 ∘c. Assume a constant pressure of 1. 00 atm.

neonofarm [45]

The work done by the water at the constant pressure is $-4.52 \times 10^6 \ J$ .

<h3>Heat required to boil the water</h3>

The heat required to boil the water is calculated as follows;

$Q = mL_v\\\\$

where;

$L_v$ is the heat of vaporization of water = 22.6 x 10⁵ J/kg
m is mass of water

$Q = 2 \times 22.6 \times 10^5\\\\Q = 4.52 \times 10^6 \ J$

<h3>Work done by the water</h3>

The work done by the water at the constant pressure is equal to the heat gained by the water.

$W = - \Delta H\\\\W = -4.52 \times 10^6 \ J$ .

Learn more about first law of thermodynamics here: brainly.com/question/2965070

4 0

3 years ago

A boy kicks a football with an initial velocity of 28.0 m/s at an angle of 30.0o above the horizontal. what is the highest eleva

sladkih [1.3K]

As the boy kicks the football with an angle, due to the effect of the gravitational force, the ball would follow a projectile path which is parabolic in nature. From this idea, we can derive equations pertaining to the maximum height that the ball would reach. At the maximum height of the ball, the velocity of the ball would be equal to zero. From the equations for projectile motion, we would obtain the equation as follows:

Maximum height = v0^2 sin^2 (theta) / 2g
Maximum height = (28.0 m / s )^2 sin^2 (30.0) / 2(9.8 m / s^2)
Maximum height = 10 m

The maximum height that the ball would reach would be 10 m.

7 0

3 years ago