Answer:
Explanation:
given,
vector product 
= 
now, expanding the vector
the vector product is equal to
Answer:
that's all I know about workdone calculation s
First I’ll show you this standard derivation using conservation of energy:
Pi=Kf,
mgh = 1/2 m v^2,
V = sqrt(2gh)
P is initial potential energy, K is final kinetic, m is mass of object, h is height from stopping point, v is final velocity.
In this case the height difference for the hill is 2-0.5=1.5 m. Thus the ball is moving at sqrt(2(10)(1.5))=
5.477 m/s.
Answer:
a = 2.5 m/s^2
Explanation:
u = 0
v = 25
t = 10
(using first eq. of motion)
a = (v - u) /t
a = (25 - 0) /10
a = 25/10
a = 2.5 m/s^2
