First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
![N= \frac{m}{m_p}= \frac{1.0 kg}{1.67 \cdot 10^{-27} kg}=6.0 \cdot 10^{26}](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7Bm%7D%7Bm_p%7D%3D%20%5Cfrac%7B1.0%20kg%7D%7B1.67%20%5Ccdot%2010%5E%7B-27%7D%20kg%7D%3D6.0%20%5Ccdot%2010%5E%7B26%7D%20%20%20)
protons
Then, the total charge is the number of protons times the charge of a single proton:
A) experimental because he isn’t sure and is testing out
i believe it's C but i'm not completely sure
Answer: 2561.7 pounds
Explanation:
If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:
(1)
Where:
is the slope of the line
is the airplane weight with 51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)
is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)
This means we already have one point of the graph, which coordinate is:
![(X_{1},Y_{1})=(51,2390.7)](https://tex.z-dn.net/?f=%28X_%7B1%7D%2CY_%7B1%7D%29%3D%2851%2C2390.7%29)
Rewritting (1):
(2)
As Y is a function of X:
(3)
Substituting the known values:
(4)
(5)
(6)
Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):
(7)
(8) This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.
Answer:
C. -0.6
Explanation:
Line is passing through the points ( - 3, 1) & (2, - 2)
Slope of line
![= \frac{ - 2 - 1}{2 - ( - 3)} = \frac{ - 3}{2 + 3} = \frac{ - 3}{5} = - 0.6 \\](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20-%202%20-%201%7D%7B2%20-%20%28%20-%203%29%7D%20%20%3D%20%20%5Cfrac%7B%20-%203%7D%7B2%20%2B%203%7D%20%20%3D%20%20%5Cfrac%7B%20-%203%7D%7B5%7D%20%20%3D%20%20-%200.6%20%5C%5C%20)