Ask question

Ask question

All categories

2 years ago

10

A 100 kg person sits on a 5 kg bicycle. The total weight is borne equally by the two wheels of the bicycle. The tires are 2.0 cm

wide and are inflated to a gauge pressure of 8.0 × 105 Pa. What length of each tire is in contact with the ground?

1 answer:

timofeeve [1]2 years ago

8 0

To solve this exercise it is necessary to take into account the concepts related to Pressure depending on the Force and the Area.

The pressure is defined as

$P =\frac{F}{A}$

Where,

$F_w = Force$

$A = Area$

Our values are given as,

$m_1 = 100Kg$

$m_2 = 5Kg$

Where $m_1$ is the mass of the person and $m_2$ is mass of cycle. Therefore the total mass at the system is 105Kg.

For Newton's second law we have:

$F = ma \rightarrow$ where a is the acceleration, in this case the same Gravitational acceleration.

We need to make two considerations, the first is to calculate the total weight and second to calculate the weight on each wheel (2), that is

$F_T = 105*9.8$

$F_T = 1030.05N$

Force in each wheel,

$F_{wheel} = \frac{1030.05}{2}$

$F_{wheel} = 515.025N$

In this way we can now calculate the length based on the pressure, that is

$P = \frac{F_T}{A}$

$P = \frac{F_T}{L*W}$

$L = \frac{F_T}{P*W}$

$L = \frac{515.025}{(8*10^{5})(2*10^{-2})}$

$L = 0.0321m$

Therefore each tire has 3.21cm

You might be interested in

P6: An object of mass m sits on a spring of constant k in an elevator that is accelerating upwards with acceleration a. a) In te

tankabanditka [31]

Answer:

(a). The spring compressed is $\dfrac{ma+mg}{k}$ .

(b). The acceleration is 1.5 g.

Explanation:

Given that,

Acceleration = a

mass = m

spring constant = k

(a). We need to calculate the spring compressed

Using balance equation

$kx-mg=ma$

$x=\dfrac{ma+mg}{k}$ ....(I)

The spring compressed is $\dfrac{ma+mg}{k}$ .

(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

The compression is given by

$x=2.5\times x_{0}$

Here, acceleration is zero

So, $x=2.5\times\dfrac{mg}{k}$

We need to calculate the acceleration

Put the value of x in equation (I)

$2.5\times \dfrac{mg}{k}=\dfrac{ma+mg}{k}$

$2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)$

$a=2.5g-g$

$a=1.5g$

Hence, (a). The spring compressed is $\dfrac{ma+mg}{k}$ .

(b). The acceleration is 1.5 g.

8 0

3 years ago

why does diving 30m below sea level affect our bodies more than being in a building 30m above sea level

Genrish500 [490]

Imagine you are in a swimming pool 30m deep. Assuming you know that water is denser than air, you would know that the 30m of water above you will carry more weight, and press down on your body. Say you were in a swimming pool 60m deep, you would be sandwiched between 30m of water pressing down on you, and the upthrust created by the 30m of water below you.

In a building 30m up, the pressure will be regulated, as you are in a building. The floor will be strong enough to support the weight of the body, and the body will not recoil into itself.

5 0

3 years ago

A 0.73-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar

Tasya [4]

Answer:

A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West

Explanation:

A) For this exercise we must use the expression of Faraday's law for a moving body

fem = $- \frac{d \phi }{dt}$

fem = $- \frac{d (B l y}{dt}= - B l v$ - d (B l y) / dt = - B lv

B = $- \frac{fem}{l \ v}$

we calculate

B = - 7.9 10⁻⁴ /(0.73 20)

B = 5.4 10⁻⁵ T

B) to determine which side of the bar is positive, we must use the right hand rule

the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.

Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West

4 0

3 years ago

⦁ Determining the magnetic flux, A rectangular piece of stiff paper measures 10 cm x 5 cm. You hold the piece of paper in a unif

MArishka [77]

Answer:

jguewjdofe

Explanation:

4 0

2 years ago

If the current in this circuit is 3 A, what must be the value of R3?<br><br><br>It's 5 Ω

Svetllana [295]

Explanation :

It is given that,

In the given figure all the three resistors are in series.

Current flowing in the circuit, $I=3\ A$

Voltage, $V=30\ V$

We know that in series circuit the current flowing in all resistors is same.

Using Ohm's law, we get:

$V=IR$

$30\ V=3\ A(2\ \Omega+3\ \Omega+R_3)$

$R_3=5\ \Omega$

Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers