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2 years ago

If you were standing at the center of curvature in front of a concave mirror, what image would be projected?

1 answer:

3 0

When you stand at the center of curvature in front of a concave mirror, the image created will be formed at the center of curvature also, but it will be inverted. The image formed will be real, and will have the same size as you.

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What is the relationship between lightning and thunder

PtichkaEL [24]

Whenever lightning strikes it separates the air where it goes. This air then rushes back together making a loud noise when it connects, creating thunder.

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3 years ago

The wavelength of the light is 0.63 micrometers. How much of this length stays in 1 centimeter

bazaltina [42]

11,066,669.
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2 years ago

Problem: Hooke's law states that the force on a spring varies directly with the distance that it is stretched. If a spring has a

Scorpion4ik [409]

Answer:

Restoring force of the spring is 50 N.

Explanation:

Given that,

Spring constant of the spring, k = 100 N/m

Stretching in the spring, x = 0.5 m

We need to find the restoring force of the spring. It can be calculated using Hooke's law as "the force on a spring varies directly with the distance that it is stretched".

$F=kx$

$F=100\ N/m\times 0.5\ m$

F = 50 N

So, the restoring force of the spring is 50 N. Hence, this is the required solution.

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3 years ago

The data table shows some data related to the Sun and the planets in our solar system.

AlexFokin [52]

You have selected the correct answer and blobbed over it with your pencil.

I assume you must have looked at Saturn's average distance, found 1427,
divided that number by 6, got 237 and change, then looked at the others,
and found that 228 was the only one that's anywhere close.

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3 years ago

Read 2 more answers

A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when

Svetllana [295]

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, $A^*$ = 10 cm² = 0.001 m²
The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²
Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

$= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896$

From supersonic isentropic table, at $\frac{A}{A^*} = 2.896$ , we can determine the following;

$M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954$

The tank pressure is calculated as follows;

$\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa$

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

Learn more about converging-diverging nozzle design here: brainly.com/question/13889483

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2 years ago