consider the motion in x-direction
= initial velocity in x-direction = ?
X = horizontal distance traveled = 100 m
= acceleration along x-direction = 0 m/s²
t = time of travel = 4.60 sec
Using the equation
X =
t + (0.5)
t²
100 =
(4.60)
= 21.7 m/s
consider the motion along y-direction
= initial velocity in y-direction = ?
Y = vertical displacement = 0 m
= acceleration along x-direction = - 9.8 m/s²
t = time of travel = 4.60 sec
Using the equation
Y =
t + (0.5)
t²
0 =
(4.60) + (0.5) (- 9.8) (4.60)²
= 22.54 m/s
initial velocity is given as
= sqrt((
)² + (
)²)
= sqrt((21.7)² + (22.54)²) = 31.3 m/s
direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg
Answer:
Friction is a force that holds back the movement of a sliding object.
Explanation:
The two types of friction: Static friction and Kinetic friction. Static friction operates between two surfaces that aren't moving relative to each other, while kinetic friction acts between objects in motion.
Answer:
The friction of the piano and the weight
Explanation:
Answer:
![v_f=0.825m/s](https://tex.z-dn.net/?f=v_f%3D0.825m%2Fs)
Explanation:
We must use conservation of linear momentum before and after the collision, ![p_i=p_f](https://tex.z-dn.net/?f=p_i%3Dp_f)
Before the collision we have:
![p_i=p_1+p_2=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=p_i%3Dp_1%2Bp_2%3Dm_1v_1%2Bm_2v_2)
where these are the masses are initial velocities of both players.
After the collision we have:
![p_f=(m_1+m_2)v_f](https://tex.z-dn.net/?f=p_f%3D%28m_1%2Bm_2%29v_f)
since they clong together, acting as one body.
This means we have:
![m_1v_1+m_2v_2=(m_1+m_2)v_f](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29v_f)
Or:
![v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}](https://tex.z-dn.net/?f=v_f%3D%5Cfrac%7Bm_1v_1%2Bm_2v_2%7D%7Bm_1%2Bm_2%7D)
Which for our values is:
![v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s](https://tex.z-dn.net/?f=v_f%3D%5Cfrac%7B%2898.5kg%29%286.05m%2Fs%29%2B%28119kg%29%28-3.5m%2Fs%29%7D%7B%2898.5kg%29%2B%28119kg%29%7D%3D0.825m%2Fs)
140 ? i’m guessing there doesn’t look like there’s much to the question