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qwelly [4]
2 years ago
7

What event will produce the greatest increase in the gravitational force between the two masses?

Physics
1 answer:
TiliK225 [7]2 years ago
6 0

Answer:

Doubling the large mass

Explanation:

Doubling the destance bewteen the masses will simply make the gravitational force weaker

same with every answer exce

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What is the connection between electrons and protons
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Answer:

Electrons and protons are connected with one another in term of charge and size.

Explanation:

  • The size of electron and proton is always same in any atom but they possess opposite charge.
  • Electron in any atom carries negative charge where as proton carries the positive charge.
  • In any neutral atom the charge between electron and proton is balanced along with the size.
  • The nucleus of any atom bounds only proton and neutron but the electron is present revolving around the nucleus.
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1) La longitud del brazo de potencia de una palanca es de 0,0035 hectómetros y la del brazo de resistencia es de 55 centímetros.
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Entonces seria 127 para vencer.

Explanation:

espero averte ayudado:-)

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3 years ago
12<br> Hot glass looks just like<br> ________ glass.<br> •Broken<br> •cold<br> •Shiny
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shiny

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If there is a break at any point in a series circuit the current will
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not work

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8 0
3 years ago
A ball with an initial velocity of 8.00 m/s rolls up a hill without slipping. (a) Treating the ball as a spherical shell, calcul
GrogVix [38]

Answer:

Part i)

h = 5.44 m

Part ii)

h = 3.16 m

Explanation:

Part i)

Since the ball is rolling so its total kinetic energy in this case will convert into gravitational potential energy

So we have

\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = mgh

here we know that for spherical shell and pure rolling conditions

v = R \omega

I = \frac{2}{3}mR^2

\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{3}mR^2)(\frac{v^2}{R^2}) = mgh

\frac{5}{6}mv^2 = mgh

h = \frac{5v^2}{6g}

h = \frac{5(8^2)}{6(9.81)} = 5.44 m

Part b)

If ball is not rolling and just sliding over the hill then in that case

\frac{1}{2}mv^2 = mgh

h = \frac{v^2}{2g}

h = \frac{8^2}{2(9.81)} = 3.16 m

3 0
3 years ago
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