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qwelly [4]
2 years ago
7

What event will produce the greatest increase in the gravitational force between the two masses?

Physics
1 answer:
TiliK225 [7]2 years ago
6 0

Answer:

Doubling the large mass

Explanation:

Doubling the destance bewteen the masses will simply make the gravitational force weaker

same with every answer exce

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A toy car accelerates from 3m/s to 5m/s in 5sec . what is the acceleration​
san4es73 [151]

Answer:

0.4

Explanation:

Because 3m/s is the initial velocity(u) and 5m/s is the final velocity(v) and time is 5 sec.

So, acceleration = v-u ÷ t

I'm confused

7 0
3 years ago
A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g
levacccp [35]

The actual weight of the gas = apparent weight + weight.

The actual weight = W_{A} + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = W_{A}

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/m^{2}

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  W_{A} + W

Learn more about density here: brainly.com/question/406690

8 0
2 years ago
C
mestny [16]

Answer:

kftisgkstisirstizurzursrus

3 0
3 years ago
USE THE PICTURE THANKS WILL GIVE B WRONG ANSWER=report lol love ya
KIM [24]

Answer:

I would have to say B THe su would rise in the west and set in the east But this is just a guess

8 0
3 years ago
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}

b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
2 years ago
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