Answer:
7.1934 x 10^12 V/m.s
Explanation:
In order to do this exercise, you need to use the correct formula. Besides that, we need to identify our data.
First we have the radius of the plates which are circular, and it's 0.1 m. The current of the loop (I) is 2.0 A, and the radius of the loop is 0.2 m.
Now with this data, we use the next formula:
I = dE/dt Eo A
Where:
dE/dt = rate of electric field
Eo = constant of permittivity of free space
A = Area of circle
Solving for dE/dT:
dE/dt = I / Eo*A
Now, the area of the circle is A = πr²
A = 3.1416 * (0.1)² = 0.031416 m²
Now solving the electric field:
dE/dt = 2 / (8.85x10^-12 * 0.031416)
dE/dt = 7.1934 x 10^12 V/m.s
C is the correct answer hope this helps :)
Answer:
0.96 m
Explanation:
First, convert km/h to m/s.
162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s
Now find the time it takes to move 20 m horizontally.
Δx = v₀ t + ½ at²
20 m = (45.08 m/s) t + ½ (0 m/s²) t²
t = 0.4436 s
Finally, find how far the ball falls in that time.
Δy = v₀ t + ½ at²
Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²
Δy = -0.96 m
The ball will have fallen 0.96 meters.
Answer:
so you know the units in the problem and answer are the same, if they aren't you have to convert them to the same units.
