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denpristay [2]
3 years ago
7

Which letter on the diagram below represents the crest of a wave?? WILL DO BRAINLIEST(:

Physics
2 answers:
MAVERICK [17]3 years ago
5 0
I think I will be c I hope this helps
Alina [70]3 years ago
5 0
Crest is that point of the wave which has maximum positive amplitude. Therefore, C represents the crest. Trough is that point of the wave which has maximum negative amplitude. The distance between successive crests or troughs is said to be wavelength. Therefore, A represents the wavelength. B represents trough.
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If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t 2 . (a) what
MAXImum [283]
Max height occurs when v = 0.
v(t) = ds(t)/dt
v(t) = 80 - 32t
0 = 80 - 32t
t = 5/2

s(5/2) = 80(5/2) - 16(5/2)^2
s(5/2) = 100
Answer: 100 ft

96 = 80t - 16t²
t = 3, 2
(80 ± √256) / 32 using the quadratic equation.

v(2) = 16
v(3) = -16
4 0
3 years ago
Calculate 2 x 10^-3cm ÷ 2.5 x 10^4cm
Mamont248 [21]
Here is your answer:

First find the notations:

2×10^-3
=0002
And...
2.5×10^4=25000

Then divide:

0002÷25000=8E-9

Your answer:
=8 x 10-8
3 0
3 years ago
hallar un numero de dos cifras sabiendo que la suma de las cifras es 12 y que la primera de ellas es el triple de la segunda
Natali [406]

Answer:

93 o 39.

Explanation:

Hola.

En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:

1. Definimos <em>x</em> como el primer dígito y <em>y</em> como el segundo, por lo tanto, como su suma es 12, escribimos:

<em>x</em> + <em>y</em> = 12

2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:

<em>x</em> = 3 <em>y</em>

De este modo, podemos resolver para <em>y</em>:

3 <em>y</em> + <em>y</em> = 12

4 <em>y</em> = 12

<em>y</em> = 12 / 4

<em>y</em> = 3

Y para <em>x</em>:

<em>x</em> = 3 <em>y</em>

<em>x</em> = 3 * 3

<em>x</em> = 9

Así, el número puede ser 93 o 39.

¡Saludos!

3 0
3 years ago
1 point
iren [92.7K]

Answer:

i need a girlfreind

Explanation:

4 0
3 years ago
The cross-section of a pipe has an area of 2.0 cm2. Calculate the flow rate (in grams per second) of a liquid with p=1.0 g/cm3 t
Maurinko [17]
<span> flow rate = velocity of fluid x area of cross section x density 
                = 42 x 2 x 1 = 84 g/s</span>
4 0
4 years ago
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