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3 years ago

Which letter on the diagram below represents the crest of a wave?? WILL DO BRAINLIEST(:

Physics

2 answers:

MAVERICK [17]3 years ago

5 0

I think I will be c I hope this helps

Alina [70]3 years ago

5 0

Crest is that point of the wave which has maximum positive amplitude. Therefore, C represents the crest. Trough is that point of the wave which has maximum negative amplitude. The distance between successive crests or troughs is said to be wavelength. Therefore, A represents the wavelength. B represents trough.

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When you squeeze spring coils together then release them, you are creating a ______ wave.

Alinara [238K]

Compressional wave! this is because you are compressing the spring coils together, thus creating a compressional wave!

5 0

3 years ago

Microwaves are electromagnetic waves used in broadcasting and telecommunications. When do these waves increase in frequency?

miskamm [114]

When they move twords you.

6 0

4 years ago

Read 2 more answers

A 35 kg child goes down a playground that is inclined at an angle of 27.5 degrees above the horizontal. Find the acceleration if

tigry1 [53]

Answer:

4.16m/s²

Explanation:

According to Newtons second law;

$\sum Fx = ma_x\\Fm - Ff = ma_x\\W sin\theta - \mu R cos \theta = ma_x\\mg sin\theta - \mu mg cos\theta = ma_x\\$

Fm is the moving force

$\mu$ is the coefficient of kinetic friction between the child and the slide

m is the mass

g is the acceleration due to gravity

a is the acceleration of the child

Substitute the given values and get the acceleration as shown;

35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a

158.38-12.88 = 35a

145.49 = 35a

a = 145.49/35

a = 4.16m/s²

Hence the acceleration of the body is 4.16m/s²

4 0

3 years ago

The reason that oscillating systems are good to use for clocks is:

Neporo4naja [7]

Answer:

A. The period of an oscillation does not depend upon amplitude.

Explanation:

The period of a spring-mass system is:

T = 1/f = 2π√(m/k)

where f is the frequency, m is the mass, and k is the spring constant.

The answer isn't B. There are no frictionless systems in the real world.

The answer isn't C or D. As shown, the frequency is a function of both the mass and the spring constant.

The answer isn't E. Turning motion into heat is not an advantage for a clock.

The correct answer is A. The period of the system does not depend on the amplitude.

6 0

3 years ago

A 0.50-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.9 m on a frictionless horizontal su

Sedaia [141]

Answer:

$\boxed {\boxed {\sf 18 \ m/s}}$

Explanation:

The ball is moving in a circle, so the force is centripetal.

One formula for calculating centripetal force is:

$F_c= \frac{mv^2}r}$

The mass of the ball is 0.5 kilograms. The radius is 1.9 meters. The centripetal force is 85 Newtons or 85 kg*m/s².

$F_c$ = 85 kg*m/s²
m= 0.5 kg
r= 1.9 m

Substitute the values into the formula.

$85 \ kg*m/s^2 = \frac{0.5 \ kg *v^2}{1.9 \ m}$

Isolate the variable v. First, multiply both sides by 1.9 meters.

$(1.9 \ m)(85 \ kg*m/s^2) = \frac{0.5 \ kg *v^2}{1.9 \ m}*1.9 \ m$

$(1.9 \ m)(85 \ kg*m/s^2) = {0.5 \ kg *v^2}$

$161.5 \ kg*m^2/s^2 = 0.5 \ kg*v^2$

Divide both sides by 0.5 kilograms.

$\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} = \frac{0.5 \ kg*v^2}{0.5 \ kg}$

$\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} =v^2$

$323 \ m^2/s^2 = v^2$

Take the square root of both sides of the equation.

$\sqrt {323 \ m^2/s^2} =\sqrt{ v^2$

$\sqrt {323 \ m^2/s^2} =v$

$17.9722007556 \ m/s =v$

The original measurements have 2 significant figures, so our answer must have the same.

For the number we found, 2 sig fig is the ones place. The 9 in the tenth place tells us to round the 7 to an 8.

$18 \ m/s =v$

The maximum speed is approximately <u>18 meters per second.</u>

8 0

3 years ago