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Pie
3 years ago
9

What type of device is a coal-fired power plant?

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

D. A heat engine that uses heat to do work

Explanation:

A coal fired power plant is a heat engine that uses heat to do work.

A heat engine is a device that is used to convert heat energy into mechanical energy .

A heat pump uses mechanical energy to produce more heat from a lower heat sink.

  • A coal power plant produces heat by firing the coal.
  • Heat from the coal combustion heats water to steam.
  • The steam is used to drive heavy turbines
  • The turbine has mechanical energy and it then produce electricity.

learn more:

Renewable resource brainly.com/question/4344417

#learnwithBrainly

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A detailed explanation of static and dynamic friction . plsssss​
Gemiola [76]

Answer:

Static friction is what keeps the box from moving without being pushed, and it must be overcome with a sufficient opposing force before the box will move. Kinetic friction (also referred to as dynamic friction) is the force that resists the relative movement of the surfaces once they're in motionExplanation:

#if you need any questions answered within mins/secs hit me up and I got you

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7 0
3 years ago
A 0.15-kg ball is thrown into the air and rises to a height of 20.0 m. How much kinetic energy did the ball initially have?
zzz [600]
IF the toss was straight upward, then the kinetic energy it got
from the toss is the gravitational potential energy it has at the top,
where it stops rising and starts falling.

Potential energy =  (mass)  x   (gravity) x (height)

                           = (0.15 kg) x (9.8 m/s²) x (20 m)

                           =      29.4 kg-m²/s²  =  29.4 joules .
7 0
2 years ago
Read 2 more answers
I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?
storchak [24]

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

5 0
2 years ago
Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon.
Fudgin [204]

Answer:

g'_h=1.096\times 10^{-5}\ m.s^{-2}

Explanation:

We know that the gravity on the surface of the moon is,

  • g'=\frac{g}{6}
  • g'=1.63\ m.s^{-2}

<u>Gravity at a height h above the surface of the moon will be given as:</u>

g'_h=\frac{G.m}{(r+h)^2} ..........................(1)

where:

G = universal gravitational constant

m = mass of the moon

r = radius of moon

We have:

  • G=6.67\times 10^{-11}\ m^3.s^{-2}.kg^{-1}
  • m=7.35\times 10^{22}\ kg
  • r=1.74\times 10^6\ m
  • h=384.4\times 10^6\ m is the distance between the surface of the earth and the moon.

Now put the respective values in eq. (1)

g'_h=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.74\times 10^6+384.4\times 10^6)^2}

g'_h=1.096\times 10^{-5}\ m.s^{-2} is the gravity on the moon the earth-surface.

4 0
3 years ago
I need help!!!!!!!
wlad13 [49]
One simple use of the elements of the electromagnetic spectrum that we use during our everyday lives is our daily use of microwave radiation. microwave radiation is absorbed by water molecules which heats up and cooks the food whilst killing bacteria. Another would be ultraviolet radiation which we use daily in things such as light bulbs. The sun also uses this. Lastly, we use radio waves constantly. May it be tv programs, radio, or our cell phones.
4 0
2 years ago
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