Answer:
Kc = 3.90
Explanation:
CO reacts with 
to form 
and 
. balanced reaction is:
No. of moles of CO = 0.800 mol
No. of moles of = 2.40 mol
Volume = 8.00 L
Concentration = 
Concentration of CO = 
Concentration of = 
Initial 0.100 0.300 0 0
equi. 0.100 -x 0.300 - 3x x x
It is given that,
at equilibrium 
= 0.309/8.00 = 0.0386 M
So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M
At equilibrium = 0.300 - 0.0386 × 3 = 0.184 M
At equilibrium = 0.0386 M
![Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2O%5D%5BCH_4%5D%7D%7B%5BCO%5D%5BH_2%5D%5E3%7D)
if 105 grams burns completely
therefore
105 ×22.4/48=49
You have to move the decimal point forward 2 times to make the number 3.4,which makes the scientific notation 3.4×10^-2
Answer:
Yes, that is correctly balanced. 2 H2 + 1 O2 = 2 H2O is already balanced.
Explanation:
If you count up the number of hydrogen atoms and oxygen atoms on each side, you will see that they are equal:
2 H2 + 1 O2 (4 hydrogen and 2 oxygen) = 2 H2O (4 hydrogen and 2 oxygen).
<h2>Hello!</h2>
The answer is: 
<h2>Why?</h2>
First, we need to look for the K molecular mass:
Also, we need to remember that 1 mol of a compound or element is equal to 
of that compound.
From the statement, we are asked to calculate how many atoms of K are present in 195,49 of K.
So, doing the calculations, we have:
So, we have atoms of K in 195,49 grams of K.
Have a nice day!
