To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.
n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
n = 0.40 mol N2
At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:
V = nRT / P
V = 0.40 x 8.314 x 293.15 / 102.7 x 10^3
V = 9.49 x 10^-3 m^3 or 9.49 L
Answer:
What type of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) metallic bonds
In what type of bonds do atoms join together because their opposite charges attract each other?
A: metallic bonds and covalent bonds
B: metallic bonds and ionic bonds
C: ionic bonds and covalent bonds
D: ionic bonds and hydrogen bonds
(answer) ionic bonds and hydrogen bonds
What types of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) hydrogen bonds
Which statement best describes the types of bonds shown in the diagram?
A: an ionic bond; the hydrogen chloride molecule has an electrical charge
B: an ionic bond; a hydrogen ion is bonding with a chlorine atom
C: a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom
D: a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
(answer) a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
Which of the following bonds is the strongest?
A: hydrogen bonds
B: metallic bonds
C: valence bonds
D: covalent bonds
(answer)
Explanation:
UwU
Answer:
D.Lowering the temperature is the best option.
Explanation:
The value of equilibrium constants aren't changed with change in the pressure or concentrations of reactants and products in equilibrium. The only thing that changes the value of equilibrium constant is a change of temperature.
In the reaction below for example;
A + B <==>C+D
If you have moved the position of the equilibrium to the right (and so increased the amount of C and D), why hasn't the equilibrium constant increased?
Let's assume that the equilibrium constant mustn't change if you decrease the concentration of C - because equilibrium constants are constant at constant temperature. Why does the position of equilibrium move as it does?
If you decrease the concentration or pressure of C, the top of the Kc expression gets smaller. That would change the value of Kc. In order for that not to happen, the concentrations of C and D will have to increase again, and those of A and B must decrease. That happens until a new balance is reached when the value of the equilibrium constant expression reverts to what it was before.
We add up all the various atoms:
C: 55
H: 72
Mg: 1
N: 4
O: 5
55 + 72 + 1 + 4 + 5
= 137
The answer is B.
$724.73 this would be the answer because if you subtract 320.50 and 86.10 from the 1056.33 then add 75 you get 724.73