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Dmitrij [34]
3 years ago
8

Someone help me with this ASAP! ^_^

Chemistry
2 answers:
ioda3 years ago
6 0
It might be the answer B
kaheart [24]3 years ago
4 0
I think it’s C sry if I’m wrong
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Which change will cause the greatest increase in the rate of reaction for this chemical reaction? 8Zn(s) + S8(s) 8ZnS(s) A. addi
Rus_ich [418]

I found another question like this. Someone answered "The best answer to this question is adding a catalyst. 

Adding a catalyst  will cause the greatest increase in the rate of reaction for this chemical reaction , 8Zn(s) + S8(s) 8ZnS(s).                                                         ---> adding a catalyst always affects the rate of a reaction."

8 0
3 years ago
Read 2 more answers
An atom of 24/11 na decays by gamma decay which atom is left after the decay
hammer [34]

Answer:

Hello There!!

Explanation:

The atom is still 24Na.

hope this helps,have a great day!!

~Pinky~

6 0
2 years ago
2 moles of substance A contains 12.04 × 1023 atoms.
professor190 [17]

Answer:

2 moles of Substance B

Explanation:

Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)

Therefore 12.04 × 10²³/ 6.02× 10²³  =  2 mole of Substance B

7 0
2 years ago
3. A 3.455-g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of
erik [133]

Answer:

Ba\ percentage\ in\ Mass=4.8\%

Explanation:

From the question we are told that:

Mass of mixture m=3.455g

Mass of Barium m_b=0.2815g

Equation of Reaction is given as

Ba2+ + H2SO4 => BaSO4 + 2 H+

Generally the equation for Moles of Barium  is mathematically given by

Since

 Moles of Ba^{2+} = Moles of BaSO_4

Therefore

 Moles of Ba^{2+}  = \frac{mass}{molar mass of BaSO4}  

 Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol

Generally the equation for Mass of Barium  is mathematically given by

 Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}  

 Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g

Therefore

 Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%    

 Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%

 Ba\ percentage\ in\ Mass=4.8\%

8 0
3 years ago
Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
sergeinik [125]

Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

Formula Used:

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density

Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
3 years ago
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