Work done = force * distance
work done = 200 * 20
work done = 4000J
Answer:
constant at the speed of light
Answer:
I = 0.451 amp
Explanation:
given,
C = 8.0 µF
V = 2 V
resistor connected between two terminal = 6 Ω
current flowing through resistor = 13 µsec
Q = CV
Q = 8 x 2
Q = 16 µC
for an RC discharge circuit
V = V_0e^{-\dfrac{t}{RC}}
I = \dfrac{-Q_0}{RC}e^{-\dfrac{t}{RC}}
t = 13 µsec
I = \dfrac{-16}{6\times 2}e^{-\dfrac{13}{6\times 2}}
I = 0.451 amp
neglecting -ve sign just to show direction.
Answer:
65.9°
Explanation:
When light goes through air to glass
angle of incidence, i = 35°
refractive index, n = 1.5
Let r be the angle of refraction
Use Snell's law


Sin r = 0.382
r = 22.5°
Now the ray is incident on the glass surface.
A = r + r'
Where, r' be the angle of incidence at other surface
r' = 60° - 22.5° = 37.5°
Now use Snell's law at other surface

Where, i' be the angle at which the light exit from other surface.

Sin i' = 0.913
i' = 65.9°