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DedPeter [7]
3 years ago
5

A rope attached to a truck pulls a 180−kg motorcycle at 9.0m/s.The rope exerts a 400−N force on the motorcycle at an angle of 15

∘ above the horizontal. a. What is the work that the rope does in pulling the motorcycle 300m?b. How will your anwer change if the speed is 12m/s? c. How will your answer change if the truck accelerates?
Physics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

115911.09915 J

Unchanged

Decreased

Explanation:

m = Mass of motorcycle = 180 kg

v = Velocity of motorcycle = 9 m/s

F = Force = 400 N

s = Displacement = 300 m

\theta = Angle above the horizontal = 15°

Work done is given by

W=Fscos\theta\\\Rightarrow W=400\times 300\times cos15\\\Rightarrow W=115911.09915\ J

The work done is 115911.09915 J

It can be seen that the force applied is constant so it does not matter if the speed of the motorcycle changes.

Tension on the rope would be

Fcos\theta-T=ma\\\Rightarrow T=Fcos\theta-ma

Work done

W=Ts\\\Rightarrow W=(Fcos\theta-ma)s

So, the work done would be reduced.

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Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
4 years ago
Calculate the force exerted by a mental ball having a mass of 70kg moving with speed of 20m/s>2
lord [1]

Answer:

F = 1400 N

Explanation:

It is given that,

Mass of the ball, m = 70 kg

It is moving with an acceleration of 20 m/s². We need to find the force exerted by the ball.

Force is given by the product of mass and acceleration. So,

F = ma

F=70\ kg\times \ 20m/s^2\\\\F=1400\ N

So, the force of 1400 N is exerted by a metal ball.

8 0
3 years ago
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notsponge [240]

Answer:

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Explanation:

6 0
3 years ago
A baseball bat balances 74.9 cm from one end. If an 0.560-kg glove is attached to that end, the balance point moves 25.3 cm towa
timurjin [86]

Answer:

The mass of the bat is 1.09 kg.

Explanation:

Given that,

The balance point of the glove, x = 74.9 cm

Mass of the glove, m = 0.56 kg

Center of mass of the baseball bat, C = 25.3 cm

Let M is the mass of the bat. The center of mass is given by the formula as :

C=\dfrac{MX+mx}{M+m}

X is 0 as it is at a end

C=\dfrac{mx}{M+m}

25.3=\dfrac{0.56\times 74.9}{M+0.56}

M = 1.09 kg

So, the mass of the bat is 1.09 kg. Hence, this is the required solution.

3 0
3 years ago
An object is projected horizontally at 18.4 m/s from the top of a 162.7 meter cliff.
miskamm [114]

Answer:

  106.03 meters  

Explanation:

The height is given by the formula for motion under the influence of gravity.

  h = -4.9t^2 +162.7

Height is 0 when ...

  0 = -4.9t^2 +162.7

  4.9t^2 = 162.7

  t^2 = 162.7/4.9

  t = √(162.7/4.9)

The horizontal distance traveled in that time is ...

  (18.4 m/s)√(162.7/4.9) s ≈ 106.03 m

The object will strike the ground about 106.03 meters from the base of the cliff.

5 0
2 years ago
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