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Darina [25.2K]
3 years ago
7

Which of the following describes the oscillation of the medium in transverse waves?

Physics
1 answer:
svp [43]3 years ago
6 0

Wave An oscillation that transfers energy and momentum.

Mechanical wave A disturbance of matter that travels along a medium. Examples include waves on a string, sound, and water waves.

Wave speed Speed at which the wave disturbance moves. Depends only on the properties of the medium. Also called the propagation speed.

Transverse wave Oscillations where particles are displaced perpendicular to the wave direction.

Longitudinal wave Oscillations where particles are displaced parallel to the wave direction.

In a transverse wave, perpendicular to the direction the wave travels, the particles are displaced. Examples of transverse waves include on a string vibrations and on the water surface ripples. By moving the slinky up and down vertically, we can create a horizontal transverse wave.

In a longitudinal wave, parallel to the direction the wave travels, the particles are displaced. Compressions that move along a slinky are an example of longitudinal waves. By pushing and pulling the slinky horizontally, we can make a horizontal longitudinal wave.

Common mistakes and misconceptions

Sometimes people forget that wave velocity is not the same as the velocity of the medium particles. How fast the disturbance travels through a medium is the wave speed. The velocity of the particle is how fast a particle moves about its position of equilibrium.

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on aircraft carriers, catapults are used to accelerate jet air craft to flight speeds in a short distance. One such catapult tak
sineoko [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) - (speed at the beginning)

The jet's change in speed = (70 m/s) - (zero) = 70 m/s

So acceleration = (70 m/s) / (2.5 s)

Acceleration = (70 / 2.5) m/s²

<em>Acceleration = 28 m/s²</em>  

That's about 2.9 G's .  Jet pilots can endure a lot more than that, but maybe the catapult or the hook on the airplane can't.  Let's look a little closer:

F = m A (Newton #2)

The force on the airplane = (18,000 kg) x (28 m/s²)

Force on the airplane = 504,000 Newtons

That's about 113,000 pounds !  Maybe the part of the airplane that the catapult pushes on can't handle any more force than that.  Or maybe that's the most force the catapult can deliver.

Also, the REACTION force on the catapult is the same 113,000 pounds.  Maybe the hooks or the chains or the struts on the catapult can't handle any more force than that.

That's almost 57 tons for gosh sakes !  Maybe the DECK of the carrier can't handle more force than that, and that's why they can't launch the airplane with acceleration of more than 2.9 G's .

8 0
3 years ago
Helppp!!! what's the answer to this??
riadik2000 [5.3K]

Answer:

(b)

Explanation:

The voltage always lags the current by 90°, regardless of the frequency.

4 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl
zysi [14]

Answer:\alpha =9.302\ rad/s^2

Explanation:

Given

mass of sphere m=250\ gm

diameter of sphere d=4.30\ cm

radius r=\frac{4.30}{2}\ cm

f=0.0200\ N

friction will provide resisting torque so

f\times r=I\times \alpha

where I=\text{moment of Inertia}

f=\text{friction force}

\alpha =\text{angular acceleration}

I=\frac{2}{5}mr^2

0.02\times r=\frac{2}{5}mr^2\times \alpha

\alpha =\frac{5}{2r}\times f

\alpha =\frac{5}{2}\times \frac{2}{4.3\times 10^{-2}}\times 0.02

\alpha =9.302\ rad/s^2

(b)time taken to decrease its rotational speed by 21\ rad/s

t=\dfrac{\Delta \omega }{\alpha }

t=\dfrac{21}{9.302}

t=2.25\ s

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